Question

我正在尝试使用for next循环迭代数组并组合其字符串我只能得到第一个数组。不知道如何编写代码与第二个组合并使用VB.NET创建第三个数组。你能帮忙吗？

前：

arrLetters() As String = {"A", "B", "C", "D", "E", "F", "G", "H", "I"}

arrNumbers() As String = {"1", "2", "3", "4", "5", "6", "7", "8", "9"}

结果array(81) = {A1, A2 ...A9, B1, B2...B9, ...I9}

Answer 1

在C＃中它将是：

from letter in arrLetters
from number in arrNumbers
select letter + number

在VB中，结果进入数组变量：

    Dim array = (From letter In arrLetters
                 From number In arrNumbers
                 Select letter + number).ToArray()

Answer 2

使用以下逻辑（在C＃中）

    var arrLetters= new string[] {"A", "B", "C", "D", "E", "F", "G", "H", "I"};
    var arrNumbers = new string[] { "1", "2", "3", "4", "5", "6", "7", "8", "9" };

    var array = arrLetters.Zip(arrNumbers, (letter, word) => letter + word);

希望这会有所帮助：）

两个数组的笛卡尔连接

2 个答案: