我已经阅读了许多关于PHP和JSONArray循环的其他问题。我正在通过我的Android设备向他们的班级和studentId发送不同学生的JSONArray值。使用这些值,我在数据库中搜索它们的名称并返回一个JSONArray。
JSON Input: [{"studentId":"2","class":"2a","dbname":"testDb"}]
<?php
$jsonString = $_POST['json']; //see comment below
$jArray = json_decode($jsonString, true);
$conn = mysql_connect('localhost', 'user', 'pwd' );
mysql_select_db('dbname', $conn);
foreach( $jArray as $obj ){
$className = $obj['class']; //String
$id= $obj['studentId']; //int
$result = mysql_query("SELECT name FROM student WHERE class='$className' AND id='$id'");
$e=mysql_fetch_assoc($result); //will only fetch 1 row of result
$output[]=$e;
}
echo (json_encode($output));
?>
的Android
HttpClient client = new DefaultHttpClient();
HttpResponse response;
try{
HttpPost post = new HttpPost("http://abc/getName.php");
List<NameValuePair> nVP = new ArrayList<NameValuePair>(2);
nVP.add(new BasicNameValuePair("json", studentJson.toString())); //studentJson is the JSON input
//student.Json.toString() produces the correct JSON [{"studentId":"2","class":"2a","dbname":"testDb"}]
post.setEntity(new UrlEncodedFormEntity(nVP));
response = client.execute(post);
if(response!=null){
//process data send from php
}
}
已解决:请参阅下面的答案
答案 0 :(得分:6)
已解决:最后了解问题所在。从Android发布到PHP脚本后,我的JSONArray变为[{\"studentId\":"2\",\"class\":\"2a\",\"dbname\":\"testDb\"}]
要删除“\”,请使用PHP命令stripslashes
花4个小时进行调试!
希望这对那些想要在Android和PHP之间发送和检索数据的人来说是一个很好的指南
答案 1 :(得分:1)
这是你的问题:
print_r(json_decode('[{"regNo":"2","class":"2a","dbname":"TestData"}]',true));
返回Array ( [0] => Array ( [regNo] => 2 [class] => 2a [dbname] => TestData ) )
,表示已解码的json放在数组
使用array_shift(json_decode($jsonString, true));
删除父数组。