我有一个如下所示的课程
public class Survey
{
public Survey()
{
SurveyResponses=new List<SurveyResponse>();
}
[Key]
public Guid SurveyId { get; set; }
public string SurveyName { get; set; }
public string SurveyDescription { get; set; }
public virtual ICollection<Question> Questions { get; set; }
public virtual ICollection<SurveyResponse> SurveyResponses { get; set; }
}
以上代码给出了以下异常
无法序列化类型的成员'SurveyGenerator.Survey.Questions' “了System.Collections.Generic.ICollection
当我将ICollection转换为List时,它正确序列化
由于它是实体框架的POCO,我无法将ICollection转换为List
答案 0 :(得分:2)
从类的外观来看,ICollection属性是否定义了外键关系?如果是这样,您就不希望公开展示这些集合。
例如:如果您正在遵循开发实体框架模型的最佳实践指南,那么您将有一个名为“问题”的单独类,它将您的两个类连接在一起,可能如下所示:
public class Question
{
[Key]
public int Id { get; set; }
public string Title { get; set; }
public string Description { get; set; }
public virtual Survey Survey { get; set; }
}
如果是这种情况,你很可能绕圈子调用问题 - &gt;调查 - &gt; ICollection - &gt;问题
我有类似的事件使用EF,MVC3来实现REST服务,并且无法序列化ICollection&lt;&gt;对象然后意识到我不需要,因为无论如何我将单独调用该对象。
为您的目的更新的课程将如下所示:
public class Survey
{
public Survey()
{
SurveyResponses=new List<SurveyResponse>();
}
[Key]
public Guid SurveyId { get; set; }
public string SurveyName { get; set; }
public string SurveyDescription { get; set; }
[XmlIgnore]
[IgnoreDataMember]
public virtual ICollection<Question> Questions { get; set; }
[XmlIgnore]
[IgnoreDataMember]
public virtual ICollection<SurveyResponse> SurveyResponses { get; set; }
}
我希望这会帮助你。
答案 1 :(得分:1)
将 ICollection&lt; T&gt; 更改为列表&lt; T&gt;
public class Survey
{
public Survey()
{
SurveyResponses=new List<SurveyResponse>();
}
[Key]
public Guid SurveyId { get; set; }
public string SurveyName { get; set; }
public string SurveyDescription { get; set; }
public virtual List<Question> Questions { get; set; }
public virtual List<SurveyResponse> SurveyResponses { get; set; }
}
答案 2 :(得分:1)
如果您不介意添加对程序集System.Runtime.Serialization的引用,则可以使用此代码,该代码将使用ICollection序列化对象,而无需更改对象的实现。下面的代码输出到字符串。您可以根据需要使用流。
private string ConvertClassToXMLString<T>(T classObject)
{
using (var stream = new MemoryStream())
{
var serializer = new DataContractSerializer(classObject.GetType());
serializer.WriteObject(stream, classObject);
return Encoding.UTF8.GetString(stream.ToArray());
}
}
答案 3 :(得分:0)
我使用了Matthew Merryfull解决方案并且有效。
由于我每次更新模型时都使用EF设计器进行实体生成,因此我会松开手动更改。我不得不改变用于生成模型的* .tt。我编辑了几行:
public string NavigationProperty(NavigationProperty navigationProperty)
{
var enbleWebService = string.Empty;
if(navigationProperty.ToEndMember.RelationshipMultiplicity == RelationshipMultiplicity.Many ){
enbleWebService = string.Format("[XmlIgnore]{0}[IgnoreDataMember]{0}", Environment.NewLine);
}
var endType = _typeMapper.GetTypeName(navigationProperty.ToEndMember.GetEntityType());
return string.Format(
CultureInfo.InvariantCulture,
"{5} {0} {1} {2} {{ {3}get; {4}set; }}",
AccessibilityAndVirtual(Accessibility.ForProperty(navigationProperty)),
navigationProperty.ToEndMember.RelationshipMultiplicity == RelationshipMultiplicity.Many ? ("ICollection<" + endType + ">") : endType,
_code.Escape(navigationProperty),
_code.SpaceAfter(Accessibility.ForGetter(navigationProperty)),
_code.SpaceAfter(Accessibility.ForSetter(navigationProperty)),
_code.Escape(enbleWebService));
}
public string NavigationProperty(NavigationProperty navigationProperty)
{
var enbleWebService = string.Empty;
if(navigationProperty.ToEndMember.RelationshipMultiplicity == RelationshipMultiplicity.Many ){
enbleWebService = string.Format("[XmlIgnore]{0}[IgnoreDataMember]{0}", Environment.NewLine);
}
var endType = _typeMapper.GetTypeName(navigationProperty.ToEndMember.GetEntityType());
return string.Format(
CultureInfo.InvariantCulture,
"{5} {0} {1} {2} {{ {3}get; {4}set; }}",
AccessibilityAndVirtual(Accessibility.ForProperty(navigationProperty)),
navigationProperty.ToEndMember.RelationshipMultiplicity == RelationshipMultiplicity.Many ? ("ICollection<" + endType + ">") : endType,
_code.Escape(navigationProperty),
_code.SpaceAfter(Accessibility.ForGetter(navigationProperty)),
_code.SpaceAfter(Accessibility.ForSetter(navigationProperty)),
_code.Escape(enbleWebService));
}
,请查看此文章
答案 4 :(得分:0)
对我来说,问题是没有默认构造函数。例: 列出MyVar; // MyClass需要一个公共构造函数