Question

我有两张桌子。产品和产品组。我用

"SELECT * FROM `product` `t` 
  WHERE (name LIKE '%test%' OR ean LIKE '%test%') 
    AND closed=0 "

搜索产品。现在我有另一个名为productgroups的表。每个产品都有自己的productgroup_id。我只需要显示那些拥有productgroup_id.closed=0的产品。如果productgroup.closed = 1它不应该显示它。

我该怎么做？

Answer 1

SELECT p.* FROM product p
INNER JOIN productgroup pg ON (pg.id = p.productgroup_id)
WHERE (p.name LIKE '%test%' OR p.ean LIKE '%test%') 
AND p.closed=0
AND pg.closed=0

Answer 2

也许我错过了问题的复杂性，但是......

SELECT * FROM
products INNER JOIN
     productgroups ON product.productGroup_id = productgroups.Id
WHERE
(products.name LIKE '%test%' OR products.ean LIKE '%test%') AND products.closed=0 and productgroups.closed = 0

应该做的伎俩

Answer 3

只需使用inner join：

SELECT
  *
FROM
  product t 
INNER JOIN 
  productgroups g ON t.productgroup_id = g.id
WHERE
  (t.name LIKE '%test%' OR t.ean LIKE '%test%') 
AND
  g.closed = 0

Answer 4

SELECT * FROM product t 
INNER JOIN productgroup pg ON t.productgroup_id = pg.id
WHERE (t.name LIKE '%test%' OR t.ean LIKE '%test%') AND t.closed=0 AND pg.Closed = 0

mysql搜索，来自另一个表的条件

4 个答案: