Question

我有来自风向标的风向数据，数据以0到359度表示。

我希望将其转换为16种不同方向的文本格式（罗盘）。

基本上我想知道是否有一种快速光滑的方式将角度读数缩放到16弦阵列以打印出正确的风向而不使用一堆if语句并检查角度范围

可以找到风向here。

谢谢！

Answer 1

编辑：

由于每22.5度有一个角度变化，方向应该在11.25度后交换手。

因此：

349-360//0-11 = N
12-33 = NNE
34-56 = NE

使用327-348（整个NNW谱图）中的值未能产生eudoxos答案的结果。在给出一些想法之后，我无法找到他逻辑中的缺陷，所以我重写了自己的...

def degToCompass(num):
    val=int((num/22.5)+.5)
    arr=["N","NNE","NE","ENE","E","ESE", "SE", "SSE","S","SSW","SW","WSW","W","WNW","NW","NNW"]
    print arr[(val % 16)]

>>> degToCompass(0)
N
>>> degToCompass(180)
S
>>> degToCompass(720)
N
>>> degToCompass(11)
N
>>> 12
12
>>> degToCompass(12)
NNE
>>> degToCompass(33)
NNE
>>> degToCompass(34)
NE

步骤：

将角度除以22.5，因为360度/ 16方向= 22.5度/方向变化。
添加.5以便在截断值时可以打破更改阈值之间的“平局”。
使用整数除法截断值（因此没有舍入）。
直接索引数组并打印值（mod 16）。

Answer 2

这是一个jve实现的steve-gregory的答案，对我有用。

function degToCompass(num) {
    var val = Math.floor((num / 22.5) + 0.5);
    var arr = ["N", "NNE", "NE", "ENE", "E", "ESE", "SE", "SSE", "S", "SSW", "SW", "WSW", "W", "WNW", "NW", "NNW"];
    return arr[(val % 16)];
}

有关逻辑的解释，请参阅his answer。

Answer 3

注意舍入，349 ... 11之间的角度应为“N”，因此首先添加半扇区（+（360/16）/ 2），然后处理溢出超过360％360，然后除以360 / 16：

["N","NNW",...,"NNE"][((d+(360/16)/2)%360)/(360/16)]

Answer 4

我检查了这个并且效果非常好并且看起来很准确。来源：Adrian Stevens的http://www.themethodology.net/2013/12/how-to-convert-degrees-to-cardinal.html

    public static string DegreesToCardinal(double degrees)
    {
        string[] caridnals = { "N", "NE", "E", "SE", "S", "SW", "W", "NW", "N" };
        return caridnals[(int)Math.Round(((double)degrees % 360) / 45)];
    }

    public static string DegreesToCardinalDetailed(double degrees)
    {
        degrees *= 10;

        string[] caridnals = { "N", "NNE", "NE", "ENE", "E", "ESE", "SE", "SSE", "S", "SSW", "SW", "WSW", "W", "WNW", "NW", "NNW", "N" };
        return caridnals[(int)Math.Round(((double)degrees % 3600) / 225)];
    }

Answer 5

我相信它更容易：

将方向移动11.25
在方向列表的末尾添加“N”以处理'over 360'，

DirTable = ["N","NNE","NE","ENE","E","ESE", "SE","SSE","S","SSW","SW","WSW", "W","WNW","NW","NNW",**"N"**]; 

wind_direction= DirTable[Math.floor((d+11.25)/22.5)];

Answer 6

我可能只是进行简单的度数除法，以获得数组中的位置或枚举值或能够为您提供所需文本的内容。只需向下划分所有部门。 360/16 = 22.5，所以你想要除以22.5来获得该位置。

String [] a = [N，NNW，NW，WNW，...，NNE]

Answer 7

Javascript功能100％正常工作

function degToCompass(num) { 
    while( num < 0 ) num += 360 ;
    while( num >= 360 ) num -= 360 ; 
    val= Math.round( (num -11.25 ) / 22.5 ) ;
    arr=["N","NNE","NE","ENE","E","ESE", "SE", 
          "SSE","S","SSW","SW","WSW","W","WNW","NW","NNW"] ;
    return arr[ Math.abs(val) ] ;
}

步骤

给出360度角
由于北方在-11.25到11.25之间，我们减去11.25的准确度
将角度除以22.5，因为360度/ 16方向= 22.5度/方向变化
Math.abs for negative仍然是北方
从答案

希望有所帮助

Answer 8

相反：

function getDir($b)
{

   $dirs = array('N'=>0, 'NNE'=>22.5,"NE"=>45,"ENE"=>67.5, 'E'=>90,'ESE'=>112.5, 'SE'=>135,'SSE'=>157.5, 'S'=>180,'SSW'=>202.5, 'SW'=>225,'WSW'=>247.5, 'W'=>270,'WNW'=>292.5,'NW'=>315,'NNW'=>237.5, 'N'=>0,'North'=>0,'East'=>90,'West'=>270,'South'=>180);
   return $dirs[$b];
}

Answer 9

这很好用

#!/usr/bin/env python

def wind_deg_to_str1(deg):
        if   deg >=  11.25 and deg <  33.75: return 'NNE'
        elif deg >=  33.75 and deg <  56.25: return 'NE'
        elif deg >=  56.25 and deg <  78.75: return 'ENE'
        elif deg >=  78.75 and deg < 101.25: return 'E'
        elif deg >= 101.25 and deg < 123.75: return 'ESE'
        elif deg >= 123.75 and deg < 146.25: return 'SE'
        elif deg >= 146.25 and deg < 168.75: return 'SSE'
        elif deg >= 168.75 and deg < 191.25: return 'S'
        elif deg >= 191.25 and deg < 213.75: return 'SSW'
        elif deg >= 213.75 and deg < 236.25: return 'SW'
        elif deg >= 236.25 and deg < 258.75: return 'WSW'
        elif deg >= 258.75 and deg < 281.25: return 'W'
        elif deg >= 281.25 and deg < 303.75: return 'WNW'
        elif deg >= 303.75 and deg < 326.25: return 'NW'
        elif deg >= 326.25 and deg < 348.75: return 'NNW'
        else: return 'N'

def wind_deg_to_str2(deg):
        arr = ['NNE', 'NE', 'ENE', 'E', 'ESE', 'SE', 'SSE', 'S', 'SSW', 'SW', 'WSW', 'W', 'WNW', 'NW', 'NNW', 'N']
        return arr[int(abs((deg - 11.25) % 360)/ 22.5)]

i = 0
while i < 360:
        s1 = wind_deg_to_str1(i)
        s2 = wind_deg_to_str2(i)
        print '%5.1f deg -> func1(%-3s), func2(%-3s), same:%s' % (i, s1, s2, ('ok' if s1 == s2 else 'different'))
        i += 0.5

Answer 10

此JavaScript适用于只需要8个基本方向并想要相应箭头的任何人。

function getCardinalDirection(angle) {
    const directions = ['↑ N', '↗ NE', '→ E', '↘ SE', '↓ S', '↙ SW', '← W', '↖ NW'];
    return directions[Math.round(angle / 45) % 8];
}

Answer 11

在Excel中使用它： VLOOKUP（MROUND（N12,22.5），N14：O29,2，FALSE）

单元格N12是指向需要答案的度数的方向。范围N14：O29正在查找扇区（A到R）：

风行业 0 A. 22.5 B. 45 C. 67.5 D. 90 E. 112.5 F. 135 G 157.5 H 180 J 202.5 K. 225升 247.5米 270 N. 292.5 P. 315问 337.5 R

Answer 12

如果你到了这里，只想将你的学位分成8个方向之一。

function degToCompass(num){
    const val =  Math.floor((num / 45) + 0.5);
    const arr = ["N","NE","E", "SE","S","SW","W","NW"];
    return arr[(val % 8)]

Answer 13

我大量使用R，因此需要解决方案。这是我想出的，并且可以很好地用于我喂食的所有可能的组合：

degToCardinal <- function(degrees) {
  val <- as.integer((degrees / 22.5) + 0.5)
  arr <- c("N","NNE","NE","ENE","E","ESE", "SE", "SSE","S","SSW","SW","WSW","W","WNW","NW","NNW")
  return(arr[((val+1) %% 16)])
}

Answer 14

想使用@eudoxos，但需要将所有部分拉在一起：

def deg_to_compass(d):
  return ["N", "NNE", "NE", "ENE", "E", "ESE", "SE", "SSE",
        "S", "SSW", "SW", "WSW", "W", "WNW", "NW", "NNW"] [math.floor(((d+(360/16)/2)%360)/(360/16))]

借用@Hristo markow来检查结果：

for i in range(0,360):
  print (i,deg_to_compass(i) == wind_deg_to_str2(i))

Answer 15

这是单行python函数：

def deg_to_text(deg):
    return ["N","NNE","NE","ENE","E","ESE", "SE", "SSE","S","SSW","SW","WSW","W","WNW","NW","NNW"][round(deg/22.5)%16]

显然，为了便于阅读/ pep8，它可以分为多行

将风向转换为文本词

15 个答案: