Question

我一直在尝试实现一个非常简单的脚本，提取受密码保护的zip文件。我创建了一个简单的zip文件（test.zip），密码为“1234”，包含2个文本文件（1.txt，2.txt），我写了这个脚本：

import zipfile

PASSWORD = "1234"

zip = zipfile.ZipFile("test.zip", "r")
zip.setpassword(PASSWORD)
zip.extractall()
zip.close()

我收到以下运行时错误：

Traceback (most recent call last):
  File "test.py", line 7, in <module>
    zip.extractall()
  File "/usr/lib/python2.7/zipfile.py", line 962, in extractall
    self.extract(zipinfo, path, pwd)
  File "/usr/lib/python2.7/zipfile.py", line 950, in extract
    return self._extract_member(member, path, pwd)
  File "/usr/lib/python2.7/zipfile.py", line 993, in _extract_member
    source = self.open(member, pwd=pwd)
  File "/usr/lib/python2.7/zipfile.py", line 934, in open
    raise RuntimeError("Bad password for file", name)
RuntimeError: ('Bad password for file', <zipfile.ZipInfo object at 0x1f3f2a8>)

我尝试使用“zip.namelist（）”和“extract（）”方法迭代+指定确切的参数如下：

zip.extract(<file_name>, path=<path>, pwd=<password>)

没有运气:( 我知道“extractall（）”的安全问题，在我的完整代码中，我将在提取过程之前进行验证，我只想弄清楚我做错了什么？

提前感谢您的帮助！

Answer 1

如评论中所示，您的加密模式可能存在问题。使用7-zip创建使用AES-256的zip文件我得到的错误与你的相同。使用ZypCrypto加密，它可以正常工作。

PyCrust 0.9.8 - The Flakiest Python Shell
Python 2.6.7 (r267:88850, Jun 27 2011, 13:20:48) [MSC v.1500 64 bit (AMD64)] on win32
Type "help", "copyright", "credits" or "license" for more information.

>>> import zipfile
>>> psw = "abcd"

#with zipcrypto encryption

>>> path= "C:/Users/joaquin/Desktop/zipcrypto.zip"
>>> zip = zipfile.ZipFile(path, "r")
>>> zip.setpassword(psw)
>>> zip.extractall("C:/Python26")
>>> zip.close()

#with AES-256 encryption

>>> path= "C:/Users/joaquin/Desktop/aes256.zip"
>>> zip = zipfile.ZipFile(path, "r")
>>> zip.setpassword(psw)
>>> zip.extractall("C:/Python26")
Traceback (most recent call last):
  File "<input>", line 1, in <module>
  File "C:\Python26\lib\zipfile.py", line 938, in extractall
    self.extract(zipinfo, path, pwd)
  File "C:\Python26\lib\zipfile.py", line 926, in extract
    return self._extract_member(member, path, pwd)
  File "C:\Python26\lib\zipfile.py", line 969, in _extract_member
    source = self.open(member, pwd=pwd)
  File "C:\Python26\lib\zipfile.py", line 901, in open
    raise RuntimeError("Bad password for file", name)
RuntimeError: ('Bad password for file', <zipfile.ZipInfo object at 0x00000000042B3948>)
>>>

此问题（仅支持传统PKWARE加密方法的zipfile）已报告为feature request for python 3.2

Answer 2

同意eryksun＆amp;华金

7z l -slt test.zip | grep Method

将显示使用的压缩方法。

7z a -p1234 -mem=ZipCrypto test.zip 1.txt 2.txt

将创建一个兼容python zipfile的zip。

7z a -p1234 -mem=AES128 test.zip 1.txt 2.txt

将创建AES加密zip。

参考http://docs.bugaco.com/7zip/MANUAL/switches/method.htm

Python - zipfile模块似乎不适用于密码

2 个答案: