我有一个运行得很好的python脚本,但是在运行pyinstaller之后,当我使用quit()
或exit()
命令时,我得到以下内容:
Makespec文件:
# -*- mode: python -*-
a = Analysis([os.path.join(HOMEPATH,'support/_mountzlib.py'), os.path.join(HOMEPATH,'support/useUnicode.py'), 'icinga.py'],
pathex=['/home/user/projects/icinga_python/releases/onefile_v1.0'])
pyz = PYZ(a.pure)
exe = EXE( pyz,
a.scripts,
a.binaries,
a.zipfiles,
a.datas,
name=os.path.join('dist', 'icinga'),
debug=False,
strip=False,
upx=True,
console=1 )
这是我在运行应用程序后看到的内容:
Traceback (most recent call last):
File "<string>", line 222, in <module>
File "<string>", line 207, in main
File "<string>", line 66, in icinga_mysql
File "<string>", line 45, in checksanity
NameError: global name 'quit' is not defined
答案 0 :(得分:17)
那是因为没有quit
命令。您正在寻找sys.exit
。
答案 1 :(得分:3)
quit
可以在pygame.locals import *
用法:
for event in pygame.event.get():
if event.type == QUIT:
pygame.quit()
sys.exit()
答案 2 :(得分:2)
def quit():
sys.exit()
self.quit_button = Button(self, text="QUIT",command = quit)