我创建一个新对象并将其绑定到表单。用户填写表单并转到预览页面。我将用户响应存储在会话中。
当用户返回编辑表单时，当我尝试从会话重新加载对象时，问题就出现了。我得到传递给选择字段的实体必须是托管错误。
任何人都知道我可能会出错的地方？下面是控制器的代码。
public function previewdealAction(Request $request){
$session = $this->getRequest()->getSession();
$coupon = $session->get('coupon');
$form = $this->createForm(new CouponType(), $coupon);
if ($request->getMethod() == 'POST') {
//bind the posted form values
$form->bindRequest($request);
//once a valid form is submitted ...
if ($form->isValid()){
//Proceed to Previewing deal
$file = $coupon->getImage();
$file->upload();
$session->set('coupon', $coupon);
$repository = $this->getDoctrine()
->getRepository('FrontendUserBundle:Coupon');
$coupons = $repository->findAll();
return $this->render('FrontendHomeBundle:Merchant:dealpreview.html.twig', array('coupon'=>$coupon, 'coupons'=>$coupons));
}
}
}
public function builddealAction(Request $request){
$em = $this->get('doctrine')->getEntityManager();
$user = $this->container->get('security.context')->getToken()->getUser();
//check for a coupon session variable
$session = $this->getRequest()->getSession();
$coupon = $session->get('coupon');
//If coupon is not set
if($coupon == NULL){
$coupon = new Coupon();
$date = new \DateTime(date("Y-m-d H:i:s"));
$coupon->setStartdate($date);
$coupon->setPosterid($user);
$session->set('coupon', $coupon);
}
$form = $this->createForm(new CouponType(), $coupon);
return $this->render('FrontendHomeBundle:Merchant:builddeal.html.twig', array(
'form' => $form->createView(),
));
}
-
namespace Frontend\HomeBundle\Form\Type;
use Symfony\Component\Form\AbstractType;
use Symfony\Component\Form\FormBuilder;
class CouponType extends AbstractType {
public function buildForm(FormBuilder $builder, array $options) {
$builder->add('couponname', 'text');
$builder->add('description', 'textarea');
$builder->add('price', 'money', array('currency' => 'USD'));
$builder->add('originalprice', 'money', array('currency' => 'USD'));
$builder->add('maxlimit', 'integer');
$builder->add('maxper', 'integer');
$builder->add('startdate', 'date', array(
'years' => array(2011, 2012, 2013, 2014),
));
$builder->add('duration', 'choice', array(
'choices' => array(
'3' => 3,
'7' => 7,
'14' => 14,
'30' => 30,
'60' => 60,
'90' => 90,
),
'expanded' => false,
'multiple' => false,
));
$builder->add('expirationdate', 'choice', array(
'choices' => array(
'30' => 30,
'60' => 60,
'90' => 90,
'180' => 180,
),
'expanded' => false,
'multiple' => false,
));
$builder->add('tip', 'integer');
$builder->add('salestax', 'choice', array(
'choices' => array(
'included' => 'Sales tax is included and will be remitted BY YOU at the appropriate tax jurisdiction',
'exempt' => 'Sales tax is exempt according to seller\'s tax jurisdiction',
'collected' => 'Sales tax will be collected BY YOU at time of deal redemption',
),
'expanded' => true,
'multiple' => false,
));
$builder->add('signature', 'text');
$builder->add('city', 'entity', array(
'class' => 'Frontend\\UserBundle\\Entity\\Cities',
'expanded' => false,
'multiple' => false,
));
$builder->add('category', 'entity', array(
'class' => 'Frontend\\UserBundle\\Entity\\Category',
'expanded' => false,
'multiple' => false,
));
$builder->add('address', new AddressType());
$builder->add('image', new DocumentType());
$builder->add('maxper', 'choice', array(
'choices' => array(
'1' => 1,
'2' => 2,
'3' => 3,
'4' => 4,
'5' => 5,
'6' => 6,
'7' => 7,
'8' => 8,
'9' => 9,
'10' => 10,
),
'expanded' => false,
'multiple' => false,
));
}
public function getDefaultOptions(array $options) {
return array(
'data_class' => 'Frontend\UserBundle\Entity\Coupon',
);
}
public function getName()
{
return 'user';
}
}
继承人优惠券类型
答案 0 :(得分：26)
我遇到了同样的问题 - 我正在使用getData()从表单中检索数据并存储在会话中。稍后，在重定向之后，我试图使用setData()重新填充同一表单的另一个实例。
我没有遇到过原生字段的问题。但是，当我的表单包含一个实体时，我收到了同样的可怕消息“必须管理传递给选择字段的实体”。
经过一番头疼之后，这个问题显然非常简单（不是全部吗？）。重定向后，实体已经脱离;解决方案只是使用EntityManager::merge()将实体重新包含到EntityManager中，从而将实体恢复为托管对象：）
// an array of form data from session
$entity = $data['my_entity'];
// merge() returns the managed entity
$entity = $this->getDoctrine()->getEntityManager()->merge($entity);
// update the form data array
$data['my_entity'] = $entity;
// Create form with form data
$form = $this->createForm(new MyFormType(), $data);
http://www.doctrine-project.org/api/orm/2.0/doctrine/orm/entitymanager.html
希望这有帮助！
答案 1 :(得分：10)
这与解决您的具体问题无关，但我想注释：
我遇到了同样的问题，可以通过删除 'by_reference' => false来解决这个问题，这在此处是不必要的，也是造成此错误的原因。
答案 2 :(得分：7)
有同样的问题并且使用了Daggah的答案，但在实体数组中添加了一个小循环，检查对象：
if ($this->get('session')->has('filters')) {
$filters = $this->get('session')->get('filters');
foreach ($filters as $key => $filter) {
if (is_object($filter)) {
$filters[$key] = $em->merge($filter);
}
}
$filterForm = $this->createForm(new FilterType(), $filters);
}
希望这有助于某人。
答案 3 :(得分：2)
我有同样的问题，两个答案都非常有用，但我的问题涉及到多维数组，所以为了保持动态，我使用了jahller函数的递归版本。
private function manageObjects(&$data_array)
{
foreach ($data_array as $key => &$value)
if (is_object($value))
$data_array[$key] = $this->container->get('doctrine.orm.entity_manager')->merge($value);
else if (is_array($value))
$this->manageObjects($value);
}
希望这有助于某人。
答案 4 :(得分：0)
基于prev评论的更复杂的解决方案。 支持ArrayCollections和DateTime对象
/**
* Merge objects
* Allow to manage object by doctrine when using stored (eg. in session data values)
* @param $data_array - list of form fields
* @return mixed
*/
public function manageObjects($data_array)
{
foreach ($data_array as $key => $value) {
// for multi choices
if ($value instanceof ArrayCollection) {
$data_array[$key] = $this->manageObjects($value);
}
//ommit dateTime object
elseif ($value instanceof \DateTime) {
}
elseif (is_object($value)) {
$data_array[$key] = $this->getService('doctrine.orm.entity_manager')->merge($value);
}
}
return $data_array;
}