使用数组下标时转储Segmentation Fault核心

Question

我正在尝试实施一个相当基本的程序，但我正在获得一个倾销核心。关于我做错的任何想法？

#include <stdio.h>

int
main(void){


    char *number [] = {"one","two","three","four","five","six","seven","eigth","nine"};
    char *object [] = {"sf","sfe","sefg","efsef","seg","eshse","segeg","ryte","asrh","asegh"};

    for(int i=0;i<10;i++){

        printf("In this code %s\n this should %s\n work\n\n",number[i],object[i]);


    }


}

Answer 1

Joe说得对：你的循环gos从0到9，即10个项目。你想要0到8。

这是一个真正常见的初学者错误。

模式是

for index = 0; while index is less than length; add one to index

Answer 2

你有一个经典的'一个接一个'的错误。 “number”数组中的元素太少。 object中有十个元素，number中只有九个元素。