我想遍历这个数组并在项目符号中显示。我知道这看起来很可疑，就像你自己一样。但是我无法克服嵌套的foreach问题，特别是当谈到线程的deph时。我在上一个问题Traverse Array and Display In Bullet Points中得到了答案，但我不确定如何更改给出的解决方案中的标记....或者如果可能的话。下面是数组，我有一个指向我想要的标记的pastebin的链接，但是如果将来可以很容易地更改标记，那就太棒了，即标记视图与逻辑分离。
Array
(
[1] => Array
(
[id] => 1
[comment_title] => comment title
[comment] => a
[comment_date] => comment date
[parent_id] => 0
[children] => Array
(
[3] => Array
(
[id] => 3
[comment_title] => comment title
[comment] => this is another comment
[comment_date] => comment date
[parent_id] => 1
[depth] => 0
[child_count] => 0
[children] =>
)
[4] => Array
(
[id] => 4
[comment_title] => comment title
[comment] => this is a third comment
[comment_date] => comment date
[parent_id] => 1
[depth] => 0
[child_count] => 0
[children] =>
)
)
[depth] => 1
[child_count] => 2
)
[2] => Array
(
[id] => 2
[comment_title] => comment title
[comment] => this is yet another comment
[comment_date] => comment date
[parent_id] => 0
[children] => Array
(
[5] => Array
(
[id] => 5
[comment_title] => comment title
[comment] => another comment
[comment_date] => comment date
[parent_id] => 2
[children] => Array
(
[7] => Array
(
[id] => 7
[comment_title] => comment title
[comment] => Hey im a comment!
[comment_date] => 1/1/1970
[parent_id] => 5
[children] => Array
(
[8] => Array
(
[id] => 8
[comment_title] => comment title
[comment] => I disagree
[comment_date] => 1/1/1970
[parent_id] => 7
[children] => Array
(
[9] => Array
(
[id] => 8
[comment_title] => comment title
[comment] => My comment is...
[comment_date] => 1/1/1970
[parent_id] => 8
[children] => Array
(
[10] => Array
(
[id] => 8
[comment_title] => comment title
[comment] => Hey im a comment!
[comment_date] => 1/1/1970
[parent_id] => 9
[depth] => 0
[child_count] => 0
[children] =>
)
)
[depth] => 1
[child_count] => 1
)
)
[depth] => 2
[child_count] => 1
)
)
[depth] => 3
[child_count] => 1
)
)
[depth] => 4
[child_count] => 1
)
[6] => Array
(
[id] => 6
[comment_title] => comment title
[comment] => This is the last comment
[comment_date] => 1/1/1970
[parent_id] => 2
[depth] => 0
[child_count] => 0
[children] =>
)
)
[depth] => 5
[child_count] => 2
)
)
这是我想要使用的标记。 http://pastebin.com/MBppxiC7
答案 0 :(得分：0)
在我之前提供给您的代码中，只需尝试添加代码片段，您就会了解其工作原理。一旦您开始理解我所制作的代码，您就可以扩展它并添加额外的功能。
答案 1 :(得分：0)
你可以尝试创建一个检查child_count的递归函数，如果它的＆gt; 1那么函数将再次遍历该数组的子键以获取子项。基本上你可以创建一个函数，并在需要时调用它。