我需要对EditText进行验证,以便我可以输入有效的
IP地址格式(?。?。?。?),例如132.0.25.225
或
网址网址格式(www.?。?),例如www.example.com
逻辑是,如果用户首先键入任何数值,则验证(IP)将执行操作
否则用户必须在任何Web字符串
之前写“www”注意:它必须执行EditText的 onKeyListener(),我的意思是当用户提供输入时
简而言之 - 我不打算检查用户何时完成输入并按OK按钮
任何想法都赞赏, 感谢。
答案 0 :(得分:12)
IP
private static final String PATTERN =
"^([01]?\\d\\d?|2[0-4]\\d|25[0-5])\\." +
"([01]?\\d\\d?|2[0-4]\\d|25[0-5])\\." +
"([01]?\\d\\d?|2[0-4]\\d|25[0-5])\\." +
"([01]?\\d\\d?|2[0-4]\\d|25[0-5])$";
public static boolean validate(final String ip){
Pattern pattern = Pattern.compile(PATTERN);
Matcher matcher = pattern.matcher(ip);
return matcher.matches();
}
URL
try {
new java.net.URI(url);
} catch(MalformedURLException e) {
// url badly formed
}
答案 1 :(得分:1)
试试这个..
public void checkIP(String Value)
{
Pattern pattern = Pattern.compile("[0-255].[0-255].[0-255].[0-255]");
Matcher matcher = pattern.matcher(Value);
boolean IPcheck = matcher.matches();
if(IPcheck)
//it is IP
else
//it is not IP
}
答案 2 :(得分:1)
这个离子对我来说非常适合检查android中的url
if (!URLUtil.isValidUrl(url)) {
Toast.makeText(this, "Invalid URL", Toast.LENGTH_SHORT).show();
return;
}
答案 3 :(得分:0)
在 EditText 和
中添加TextWatcherafterTextChanged (Editable s)
使用正则表达式验证输入,如果输入字符与正则表达式不匹配,只需使用以下方法删除它。
Editable.delete(int start, int end)
答案 4 :(得分:0)
这是一个不同的IP地址验证解决方案,但也可用作网址验证的参考。
EditText ipText = (EditText) findViewById(R.id.ip_address);
ipText.setKeyListener(IPAddressKeyListener.getInstance());
.........
public class IPAddressKeyListener extends NumberKeyListener {
private char[] mAccepted;
private static IPAddressKeyListener sInstance;
@Override
protected char[] getAcceptedChars() {
return mAccepted;
}
/**
* The characters that are used.
*
* @see KeyEvent#getMatch
* @see #getAcceptedChars
*/
private static final char[] CHARACTERS =
new char[] { '0', '1', '2', '3', '4', '5', '6', '7', '8', '9', '.' };
private IPAddressKeyListener() {
mAccepted = CHARACTERS;
}
/**
* Returns a IPAddressKeyListener that accepts the digits 0 through 9, plus
* the dot character, subject to IP address rules: the first character has
* to be a digit, and no more than 3 dots are allowed.
*/
public static IPAddressKeyListener getInstance() {
if (sInstance != null)
return sInstance;
sInstance = new IPAddressKeyListener();
return sInstance;
}
/**
* Display a number-only soft keyboard.
*/
public int getInputType() {
return InputType.TYPE_CLASS_NUMBER | InputType.TYPE_NUMBER_FLAG_DECIMAL;
}
/**
* Filter out unacceptable dot characters.
*/
@Override
public CharSequence filter(CharSequence source, int start, int end, Spanned dest, int dstart, int dend) {
if (end > start) {
String destTxt = dest.toString();
String resultingTxt = destTxt.substring(0, dstart)
+ source.subSequence(start, end)
+ destTxt.substring(dend);
if (!resultingTxt.matches("^\\d{1,3}(\\.(\\d{1,3}(\\.(\\d{1,3}(\\.(\\d{1,3})?)?)?)?)?)?")) {
return "";
} else {
String[] splits = resultingTxt.split("\\.");
for (int i = 0; i < splits.length; i++) {
if (Integer.valueOf(splits[i]) > 255) {
return "";
}
}
}
}
return null;
}
}
答案 5 :(得分:0)
应该使用java.net.InetAddress类。您可以检查所有IP地址格式:主机地址(例如:132.0.25.225)或主机名(例如:www.google.com); IPv4或IPv6格式没问题。
源代码应该在工作线程上运行,因为有时InetAddress.getAllByName(mStringHost)需要很长时间。例如:您从主机名获取地址。
Thread mThread = new Thread(new Runnable() {
@Override
public void run() {
try {
String mStringHost = "www.google.com";
//String mStringHost = "192.168.1.2";
InetAddress[] list_address = InetAddress.getAllByName(mStringHost);
if(list_address != null && list_address.length >=1){
InetAddress inetAddress = list_address[0];
Log.d("test","inetAddress ="+ inetAddress.getHostAddress());
if( inetAddress instanceof Inet4Address){
//IPv4 process
}else{
//IPv6 process
}
}else{
throw new Exception("invalid address");
}
}catch(Exception e){
Log.e(TAG,"other exception",e);
Toast.makeText(context, "Invalid host address or host name", Toast.LENGTH_SHORT).show();
//process invalide ip address here
}
}
});
mThread.start()