如何得到术语的概括。序言

Question

例如 - 我有一些条款：

moves(1, [1]).
moves(1, [2]).
moves(1, [3]).

我怎样才能获得下学期？

moves(1, [1,2,3]).

---

% I have
    moves(1, [1]).
    moves(1, [2]).
    moves(1, [3]).

% I need to write some predicate which
    transform_moves :- 
        % ...
        % ...
        assert(moves(Pos, Arr)),

        % moves(1, [1,2,3]).

Answer 1

程序：

:- dynamic moves/2.

moves(1, [1]).
moves(1, [2]).
moves(1, [3]).

transform_moves(Pos) :- 
    findall(Y, moves(Pos, [Y]), L), 
    retractall(moves(Pos, _)),
    assert(moves(Pos, L)).

呼叫：

?- transform_moves(1).