Question

我在google开发者网站上运行YouTubeSample。我的代码没有错误，我的导入似乎没问题。但是当我运行项目时，我得到了上述错误。

我做了一些搜索，但说实话，我一直无法解决问题所在。我已经尝试过导入一个外部jar番石榴，但它没有帮助。

感谢任何帮助。这是完整的课程

package com.pengilleys.googlesamples;
import java.io.IOException;
import java.util.List;

import com.google.api.client.googleapis.GoogleHeaders;
import com.google.api.client.googleapis.json.JsonCParser;
import com.google.api.client.http.GenericUrl;
import com.google.api.client.http.HttpRequest;
import com.google.api.client.http.HttpRequestFactory;
import com.google.api.client.http.HttpRequestInitializer;
import com.google.api.client.http.HttpTransport;
import com.google.api.client.http.javanet.NetHttpTransport;
import com.google.api.client.json.JsonFactory;
import com.google.api.client.json.jackson.JacksonFactory;
import com.google.api.client.util.Key;

public class YouTubeSample {

 public static class VideoFeed {
@Key List<Video> items;
}

public static class Video {
@Key String title;
@Key String description;
@Key Player player;
}

public static class Player {
@Key("default") String defaultUrl;
}

public static class YouTubeUrl extends GenericUrl {
@Key final String alt = "jsonc";
@Key String author;
@Key("max-results") Integer maxResults;

YouTubeUrl(String url) {
  super(url);
}
}

public static void main(String[] args) throws IOException {
// set up the HTTP request factory
HttpTransport transport = new NetHttpTransport();
final JsonFactory jsonFactory = new JacksonFactory();
HttpRequestFactory factory = transport.createRequestFactory(new    HttpRequestInitializer() {

  @Override
  public void initialize(HttpRequest request) {
    // set the parser
    JsonCParser parser = new JsonCParser();
    parser.jsonFactory = jsonFactory;
    request.addParser(parser);
    // set up the Google headers
    GoogleHeaders headers = new GoogleHeaders();
    headers.setApplicationName("Google-YouTubeSample/1.0");
    headers.gdataVersion = "2";
    request.headers = headers;
  }
});
// build the YouTube URL
YouTubeUrl url = new YouTubeUrl("https://gdata.youtube.com/feeds/api/videos");
url.author = "searchstories";
url.maxResults = 2;
// build the HTTP GET request
HttpRequest request = factory.buildGetRequest(url);
// execute the request and the parse video feed
VideoFeed feed = request.execute().parseAs(VideoFeed.class);
for (Video video : feed.items) {
  System.out.println();
  System.out.println("Video title: " + video.title);
  System.out.println("Description: " + video.description);
  System.out.println("Play URL: " + video.player.defaultUrl);
}

} }

Answer 1

setup documentation给出了依赖项列表：

根据您正在构建的应用程序，您可能还需要这些依赖项：


Apache HTTP Client version 4.0.3

Google Guava version r09

Jackson version 1.6.7

Google GSON version 1.6

在这种情况下，看起来它是缺少的番石榴。我不知道你对“导出”Guava的意思，但是如果你在运行代码时在类路径中包含了Guava r09 jar文件，它应该没问题。

Answer 2

);以上的额外// build the YouTube URL是什么意思，是否意味着在该行上关闭main？

线程“main”中的Google+ API异常java.lang.NoClassDefFoundError：com / google / common / base / Preconditions

2 个答案: