Question

这就是我当前查询设置的方式：

SELECT * , (    
SELECT COUNT( * ) 
FROM paintings
WHERE id > 4000
) AS total
FROM paintings
WHERE id > 4000
LIMIT 0 , 30

如果我将查询分开，一切正常，但如果我保持这样，分页会在页面末尾显示1个ID。

选择不在每一行但不是全部返回的计数会有什么更好的选择？

例如：如果我在mysql中传递它，这是我目前得到的：

> +--------+------------+--------+
> |  id    | title      | count  |
> +--------+------------+--------+
> | 2345   | water      |   25   | 
> | 2346   | bread      |   25   | 
> | 2347   | coke       |   25   | 
> | 2348   | beer       |   25   | 
> | 2349   | oranges    |   25   | 
> +--------+------------+--------+

干杯！

Answer 1

没有，你做到了。只需运行2个查询

SELECT 
     *
FROM 
     paintings
WHERE 
     id >4000
LIMIT 
     0 , 30;

SELECT 
    COUNT( * ) as total
FROM 
    paintings
WHERE 
    id >4000

Answer 2

除了发表的内容之外。仍有2个查询，但更清洁一点：

# The main query
SELECT SQL_CALC_FOUND_ROWS * FROM paintings
WHERE id > 4000
LIMIT 0, 30;

# And after get the total
SELECT FOUND_ROWS() AS total;

如何在PHP中使用COUNT正确使用COUNT？

2 个答案: