基类具有函数f。 派生类会覆盖函数f。 我想为派生类的对象调用基类'f。我怎么能这样做?
以下是代码示例。
classdef base
methods ( Access = public )
function this = f( this )
disp( 'at base::f' );
end
end
end
classdef derived < base
methods ( Access = public )
function this = f( this )
% HERE I WANT TO CALL base::f
this@base.f(); % this is an error
disp( 'at derived::f' );
end
end
end
d = derived();
d.f();
% here the result should be
% at base::f
% at derived::f
答案 0 :(得分:8)
而不是
this@base.f();
它是
f@base(this)