使用jquery ajax将值从表单的文本字段传递给php

时间:2011-09-16 12:05:46

标签: php jquery

我想到的是一个警告框,用于在按下按钮后向用户询问文本字段中指定的名称

<html>
<head>
<script type="text/javascript" src="jquery-1.6.3.js"></script>
<script type="text/javascript">
$(document).ready(function(){


  $("#btnSubmit").click(function(e){
   e.preventDefault();

     $.ajaxSetup ({  
        cache: false  
     }); 

     dataString = $("#testform").serialize();

     $.ajax({
        type: "POST",
    url: "test.php",
    data: dataString,
    success: function(data){
        alert(data);
    }
      }); 
  });


});
</script>
</head>


<body>
  <form id="testform">
    <input type="text" name="jeds" value="jed" id="jedid">
  </form>    
  <input type="button" id="btnSubmit" value="submit">    
</body>

test.php的

    <?PHP
        if ($_SERVER['REQUEST_METHOD'] == 'POST') {
        $name = $_POST['name'];
        print "hello " . $name;
        }
    ?>

我不确定为什么它无法抓住这个名字。

3 个答案:

答案 0 :(得分:2)

更改

<form id="testform">
<input type="text" name="jeds" value="jed" id="jedid">
</form>

<input type="button" id="btnSubmit" value="submit">

<form id="testform" method="post">
    <input type="text" name="jeds" value="jed" id="jedid">
    <input type="button" id="btnSubmit" value="submit">
</form>

if ($_SERVER['REQUEST_METHOD'] == 'POST') {
    $name = $_POST['name'];
    print "hello " . $name;
}

if ($_SERVER['REQUEST_METHOD'] == 'POST') {
    $name = $_POST['jeds'];
    print "hello " . $name;
}

答案 1 :(得分:1)

<input type="text" name="jeds" value="jed" id="jedid">

应该是

<input type="text" name="name" value="jed" id="jedid">

答案 2 :(得分:1)

我认为你没有在表单标签中提到过该方法(默认情况下是GET)。您从$ _POST请求变量。将方法名称命名为post