Question

我可能错过了一些非常明显的东西。我试图在Cake中将多个表连接在一起，但我只从第一个表中获取字段。请考虑以下代码..

$joins = array();
$joins[] =  array(
            'table' => 'products', 
            'alias' => 'Product', 
            'type' => 'LEFT',
            'conditions' => array(
                'Device.id = Product.device_id'
            )
    );

$joins[] =  array(
            'table' => 'pricepoints', 
            'alias' => 'Pricepoints', 
            'type' => 'LEFT',
            'conditions' => array(
                'Pricepoints.product_id = Product.id'
            )
    ); 
$all_products = $this->Device->find('all', array("joins" => $joins);

这将返回以下SQL

SELECT `Device`.`id`, `Device`.`manufacturer_id`, `Device`.`name`, `Device`.`type_id`, `Manufacturer`.`id`, `Manufacturer`.`name` FROM `devices` AS `Device` LEFT JOIN products AS `Product` ON (`Device`.`id` = `Product`.`device_id`) LEFT JOIN pricepoints AS `Pricepoints` ON (`Pricepoints`.`product_id` = `Product`.`id`) LEFT JOIN `manufacturers` AS `Manufacturer` ON (`Device`.`manufacturer_id` = `Manufacturer`.`id`)

即。它只返回父模型中的字段ie。设备。如何从连接中选择所有字段？我认为它与我建立模型关系的方式有关，但我认为我已经正确设置了这些。

有人建议吗？

Answer 1

您可以在查询查询中指定字段：

$all_products = $this->Device->find('all', array("fields" => array('Device.*','Product.*','Pricepoints.*')
                                                 "joins" => $joins
);

希望这有帮助

Answer 2

通过调用bindModel（）而不是手动指定连接来进行连接。有关creating and destroying associations on the fly

的详细信息，请参阅食谱

CakePHP模型连接问题，连接表中缺少字段。

2 个答案: