Question

我想删除xsl创建的元素。我在创建元素后检查子项。例如

<projectRisks>    (element to be removed if it empty after creation)

 <for-each risk>

  <if riskid=projid >

      COPY RISK

  </if >

 </foreach>

<projectRisks>

完成此操作后，如果projectRisks没有子项，我需要将其删除。我尝试了这里提供的所有解决方案。但是，由于在xsl中创建的projectRisks，无法删除它。

这里我提供了示例XML

 <addProjectDetail>
<uniqueProjectId>142</uniqueProjectId>
</addProjectDetail>
<addProjectDetail>
<uniqueProjectId>915</uniqueProjectId>
</addProjectDetail>
<addProjectDetail>
<uniqueProjectId>100</uniqueProjectId>
</addProjectDetail>
  <addProjectRisks>
    <addProjectRisk>
        <uniqueProjectId>142</uniqueProjectId>
        <agencyProjectRiskId>852</agencyProjectRiskId>              
    </addProjectRisk>
   <addProjectRisk>
    <uniqueProjectId>915</uniqueProjectId>
    <agencyProjectRiskId>853</agencyProjectRiskId>  
    </addProjectRisk>   
   </addProjectRisks>

结果xml看起来像

   <addProjectDetail>
   <uniqueProjectId>142</uniqueProjectId>
      </addProjectDetail>
<addProjectRisks>
    <addProjectRisk>
        <uniqueProjectId>142</uniqueProjectId>
        <agencyProjectRiskId>852</agencyProjectRiskId>              
    </addProjectRisk>
</addProjectRisks>
<addProjectDetail>
<uniqueProjectId>915</uniqueProjectId>
</addProjectDetail>
<addProjectRisks>
    <addProjectRisk>
        <uniqueProjectId>915</uniqueProjectId>
         <agencyProjectRiskId>853</agencyProjectRiskId>             
    </addProjectRisk>
</addProjectRisks>
 <addProjectDetail>
<uniqueProjectId>100</uniqueProjectId>
</addProjectDetail>

在上面的xml中，有3个代码，142,915和100。匹配142和915有2个风险，100个没有风险因此，对于100，它不应该创建addProjectRisks元素

Answer 1

您可以使用此变换，我已使用模式，以便简化当前（未显示）样式表中的集成：

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <xsl:output omit-xml-declaration="yes" indent="yes"/>
    <xsl:strip-space elements="*"/>

    <xsl:key name="ProjectRiskById" match="addProjectRisk" use="uniqueProjectId"/>

    <xsl:template match="addProjectDetail">
        <xsl:copy-of select="."/>
        <xsl:apply-templates select="key('ProjectRiskById',uniqueProjectId)[1]" 
            mode="add"/>
    </xsl:template>

    <xsl:template match="addProjectRisk" mode="add">
        <addProjectRisks>
            <xsl:copy-of select="key('ProjectRiskById',uniqueProjectId)"/>
        </addProjectRisks>
    </xsl:template>

    <xsl:template match="text()"/>

</xsl:stylesheet>

当应用于以下输入样本时（更改为通过添加最顶层元素使其格式良好并使其覆盖更多情况）：

<xml>
    <addProjectDetail>
        <uniqueProjectId>142</uniqueProjectId>
    </addProjectDetail>
    <addProjectDetail>
        <uniqueProjectId>915</uniqueProjectId>
    </addProjectDetail>
    <addProjectDetail>
        <uniqueProjectId>100</uniqueProjectId>
    </addProjectDetail>

    <addProjectRisks>
        <addProjectRisk>
            <uniqueProjectId>142</uniqueProjectId>
            <agencyProjectRiskId>852</agencyProjectRiskId>              
        </addProjectRisk>
        <addProjectRisk>
            <uniqueProjectId>915</uniqueProjectId>
            <agencyProjectRiskId>853</agencyProjectRiskId>  
        </addProjectRisk>   
                <addProjectRisk>
            <uniqueProjectId>915</uniqueProjectId>
            <agencyProjectRiskId>857</agencyProjectRiskId>  
        </addProjectRisk> 
    </addProjectRisks>
</xml>

制作此片段：

<addProjectDetail>
   <uniqueProjectId>142</uniqueProjectId>
</addProjectDetail>
<addProjectRisks>
   <addProjectRisk>
      <uniqueProjectId>142</uniqueProjectId>
      <agencyProjectRiskId>852</agencyProjectRiskId>
   </addProjectRisk>
</addProjectRisks>
<addProjectDetail>
   <uniqueProjectId>915</uniqueProjectId>
</addProjectDetail>
<addProjectRisks>
   <addProjectRisk>
      <uniqueProjectId>915</uniqueProjectId>
      <agencyProjectRiskId>853</agencyProjectRiskId>
   </addProjectRisk>
   <addProjectRisk>
      <uniqueProjectId>915</uniqueProjectId>
      <agencyProjectRiskId>857</agencyProjectRiskId>
   </addProjectRisk>
</addProjectRisks>
<addProjectDetail>
   <uniqueProjectId>100</uniqueProjectId>
</addProjectDetail>

删除XSL创建的空节点

1 个答案: