类别opencart上的条件标签

时间:2011-09-16 05:54:00

标签: php opencart

我正在使用opencart v.1.5.1 /catalog/view/theme/default/template/product/category.tpl

我该怎么写这样的条件:

If main current display is of a parent category:
show this image

else (if it's a subcategory display ):
show different image

因为这是我想要实现的目标:

此网站上的

(父类别):http://www.guitarplayback.com/Jam-Tracks 这是一个横幅图像

子类别上的

http://www.guitarplayback.com/Jam-Tracks/Ballad-Jam-Tracks 这是右侧描述的图像

2 个答案:

答案 0 :(得分:3)

尚未对此进行测试,但这对您有用 在控制器/产品/ category.php 之前尝试此操作 $ this-> data ['products'] = array();

$categories = $this->model_catalog_category->getCategories(0);

foreach ($categories as $category) {
  if ($category['category_id'] == $category_id && $category['top']) {
     $this->data['topCatImage'] = '1';
  }
}

在category.tpl

if (isset($topCatImage)) {
   show this image
} else {
   show other image
}

答案 1 :(得分:0)

从事类似工作。希望它能帮助别人,打破一些代码:

<强>目录\控制器\产品

$cat_array = explode ("_", $path);
$top_cat_id = $cat_array[0];            
$cat_Image = $this->model_catalog_category->getCatImage($top_cat_id);
if ($cat_Image) {
    //show this image
    $this->data['image'] = $cat_Image['image'];
} 

<强>目录\模型\目录

 public function getCatImage($category_id) {

    $query = $this->db->query("SELECT image FROM " . DB_PREFIX . 
    "category AS cat LEFT JOIN category AS cats ON cats.parent_id = cat.category_id WHERE cat.parent_id =0 AND cat.category_id = '" . (int)$category_id . "'");

    return $query->row;

}

<强>目录\视图\主题\默认\模板\产品

 <?php if ($image) { ?>
       <div class="image"><img src="<?php echo $image; ?>" alt="<?php echo $heading_title; ?>" /></div>
 <?php } else { ?>
       <div class="image"><img src="<?php echo $OTHERimage; ?>" alt="<?php echo $heading_title; ?>" /></div> 
 <?php } ?>