我正在编写一个程序，一次打开一个文件，对其进行解析，然后将解析后的数据输出到一个新的.txt文档中，该文档根据文件进入而命名。有超过50个文件正在运行被阅读和解析。
因此，如果已打开的文件的名称如下：STACK-OVERFLOW-125663-D2.txt，则输出文件将类似于此125663-D2.txt。
每次读取文件时，都会解析其部件号。每个文件将包含与此类似的行（第8个分隔的逗号值（即119082,119083,119040,119085,119084）是部件号值。）：
"00003",6,"D","C20",-70.10,42.06,90.00,"119082",0,1,2,0,0,"",0,"001"
"00004",6,"D","C21",-67.91,42.06,90.00,"119082",0,1,2,0,0,"",0,"001"
"00005",13,"D","C23",-66.91,59.07,180.00,"119083",0,1,2,0,0,"",0,"002"
"00006",13,"D","R10",-77.32,66.88,90.00,"119040",0,1,2,0,0,"",0,"003"
"00007",13,"D","L3",-77.64,77.48,90.00,"119085",0,1,2,0,0,"",0,"004"
"00008",20,"D","D1",-62.91,103.77,0.00,"119084",0,1,2,0,0,"",0,"005"
"00009",21,"D","D1",-25.83,103.77,0.00,"119084",0,1,2,0,0,"",0,"005"
"00010",14,"D","L3",-40.56,77.48,90.00,"119085",0,1,2,0,0,"",0,"004"
"00011",14,"D","R10",-40.24,66.88,90.00,"119040",0,1,2,0,0,"",0,"003"
现在我需要做的是检查另一个.txt文件..让我们说它被称为“DATABASE.txt”，看看这些部件号是否已存在。此数据库文件如下所示：
119082: 125663-D2, 123456-A1,
119083: 125663-D2,
119085: 125663-D2, 123456-A1, 987654321-Z11234, 1111111-B50
因此，在DATABASE.txt文件和上面打开的文件中，我想检查打开文件中的所有部件号，看看它们是否存在于数据库中。
如果该部件确实存在，我想将文件名（输出文件）连接到找到部件号的行的末尾。
如果该部件不存在，我想将该部件添加到文件中并使用list.Sort()对文件进行排序。
我不确定如何做到这一点，任何人都可以帮忙吗？
以下是我目前的一些代码：
List<string> partNumberLines = new List<string>();
string file = openFile.FileName;
string splitFile = file.Split('\\');
string[] savedName = splitFile[splitFile.Length - 1].Split('.');
string[] lineNumber = savedNamed[2].Split('-');
string fileName = savedNamed[1] + "-" + lineNumber[0] + ".txt";
foreach (string line in fileList)
{
string[] splitLine = line.Split('\n');
for (int i = 0; i < splitLine.Length; i++)
{
string tempSplit = splitLine[i].Split(','); // splits each line by commas
if (tempSplit.Length.Equals(16))
{
tempSplit[7] = tempSplit[7].TrimStart('"'); //trims the quotes from the part numbers
tempSplit[7] = tempSplit[7].TrimEnd('"');
}
}
}
partNumberLines = partNumberLines.Distinct().ToList(); //gets rid of duplicate partnumbers in one file.
所以我的代码获取了所有的部件号和文件的名称..我只是不知道如何打开现有文件（如果它不存在，创建它）并搜索文件和在列表 partNumberLines中查找匹配项。如果匹配，则将文件名连接到当前行。如果不匹配，请创建一个新行并添加部件号和文件名，然后按部件号以数字方式对文件进行排序。
任何人都可以帮我解决这个问题吗？
答案 0 :(得分：2)
希望你没有放弃。这是一个示例类。我从上一篇文章中完成了它。将上面的数据库数据保存到database.txt，将您的零件数据保存到parts.txt，然后修改路径以查看其工作原理。希望它能帮到你。如果您还有其他问题，请随时提出。
using System;
using System.IO;
using System.Collections.Generic;
using System.Linq;
using System.Text;
namespace ConsoleApplication1
{
class Program
{
private class DataBaseRecord
{
public string PartNumber { get; set; }
public List<string> FileNames { get; set; }
public DataBaseRecord(string _PartNumber, List<string> _FileNames)
{
PartNumber = _PartNumber;
FileNames = _FileNames;
}
}
private class DataBase
{
public string databaseFile { get; set; }
List<DataBaseRecord> records;
public DataBase(string _databaseFile)
{
databaseFile = _databaseFile;
records = new List<DataBaseRecord>();
}
public void AddRecord(string partNumber, string fileName)
{
if (string.IsNullOrWhiteSpace(partNumber))
return;
if (string.IsNullOrWhiteSpace(fileName))
return;
bool exists = records.Count(x => x.PartNumber == partNumber) > 0;
if (!exists)
{
records.Add(new DataBaseRecord(partNumber, new List<string>() { fileName }));
}
else
{
var record = from x in records where x.PartNumber == partNumber select x;
foreach (DataBaseRecord dbr in record)
{
exists = dbr.FileNames.Count(x => x == fileName) > 0;
if (!exists)
dbr.FileNames.Add(fileName);
}
}
}
public void Read()
{
// read all database records into data structure
using (StreamReader sr = new StreamReader(databaseFile))
{
while (!sr.EndOfStream)
{
string line = sr.ReadLine();
string partNumber = line.Split(':')[0].Trim();
if (partNumber[0] == '\"')
partNumber = partNumber.Substring(1, partNumber.Length - 2);
string[] files = line.Split(new string[]{":"}, StringSplitOptions.None)[1].Split(new string[]{","}, StringSplitOptions.RemoveEmptyEntries);
List<string> fileNumbers = new List<string>();
foreach (String file in files)
{
if (!string.IsNullOrWhiteSpace(file))
{
fileNumbers.Add(file.Trim());
}
}
records.Add(new DataBaseRecord(partNumber, fileNumbers));
}
}
}
public void Write()
{
// write out database using the records
var sortedRecords = from x in records orderby x.PartNumber select x;
using (StreamWriter sw = new StreamWriter(databaseFile))
{
foreach (DataBaseRecord record in sortedRecords)
{
string line = record.PartNumber + ": ";
for (int index = 0; index < record.FileNames.Count; index++)
{
line += record.FileNames[index];
if (index < record.FileNames.Count - 1)
line += ", ";
}
sw.WriteLine(line);
}
}
}
}
static void Main(string[] args)
{
// replace with name of your database
DataBase db = new DataBase(@"C:\Users\jondoe\Desktop\DataBase.txt");
db.Read();
// replace with list of your parts files
string[] partsFiles = new string[] { @"C:\Users\jondoe\Desktop\parts.txt" };
foreach (string partsFile in partsFiles)
{
using (StreamReader sr = new StreamReader(partsFile))
{
while (!sr.EndOfStream)
{
string line = sr.ReadLine();
string partNumber = line.Split(new string[] { "," }, StringSplitOptions.None)[7];
if (partNumber[0] == '\"')
partNumber = partNumber.Substring(1, partNumber.Length - 2);
db.AddRecord(partNumber, Path.GetFileNameWithoutExtension(partsFile));
}
}
}
db.Write();
}
}
}
修改
如果您想要一个静态数据库并且想要允许用户选择零件文件，那么您可以在按钮单击事件中执行此操作：
private void btnOpenFile_Click(object sender, EventArgs e)
{
DataBase db = new DataBase(@"C:\Users\JonDoe\Desktop\DataBase.txt");
db.Read();
using (OpenFileDialog ofd = new OpenFileDialog())
{
if (ofd.ShowDialog() == System.Windows.Forms.DialogResult.OK)
{
using (StreamReader sr = new StreamReader(ofd.FileName))
{
while (!sr.EndOfStream)
{
string line = sr.ReadLine();
string partNumber = line.Split(new string[] { "," }, StringSplitOptions.None)[7];
if (partNumber[0] == '\"')
partNumber = partNumber.Substring(1, partNumber.Length - 2);
db.AddRecord(partNumber, Path.GetFileNameWithoutExtension(ofd.FileName));
}
}
db.Write();
}
}
}
答案 1 :(得分：1)
请勿自行解析CSV。使用FileHelpers库。可能存在很多异常，FileHelpers可以很好地处理这些异常。
其次，你正在做足够的数据操作是一个简单的数据库可能会有所帮助。也许是SQL Express，或单个文件嵌入式数据库（SQL Server Compact，SQLite）。
最后要手动执行此操作，您只需在内存中构建表。您真正拥有的是部件号和文件之间的多对多关系。所以你有两个表和一个连接表。
现在，因为“filename”在您的示例中只有一个属性（ filename ），所以它可以作为附加列附加在连接表中。所以你有2张桌子。第二个看起来像
JoinTable
-------------------
PartNum | Varchar
Filename| Varchar
你已经拥有的第一张表。
因此，如果您使用List<List<string>>在内存中复制这两个表，您应该可以使用LINQ完成此操作而不会遇到任何问题。虽然我个人会建立新的类或至少结构来代表两个表元组。
希望这有帮助。
答案 2 :(得分：0)
这里有一个快速的运行..它绝对可以使用改进，但它是一个开始：）
using System;
using System.Collections.Generic;
using System.Configuration;
using System.IO;
using System.Linq;
using System.Text;
namespace ConsoleApplication2
{
public class FileIo
{
private Dictionary<int, CommaDelimitedStringCollection> dataBase;
private const string DATABASE_PATH = @"D:\Temp\Test\DATABASE.txt";
public void Run()
{
var files = new List<string> { @"D:\Temp\Test\Test1.txt", @"D:\Temp\Test\Test2.txt", @"D:\Temp\Test\Test3.txt" };
dataBase = GetDatabase();
foreach (var file in files)
{
Search(file, GetPartNumbers(file));
}
WriteFileContents(DATABASE_PATH, BuildPartsDbStr());
}
private void Search(string fileName, List<int> partNums)
{
foreach (var partNum in partNums)
{
var path = Path.GetFileNameWithoutExtension(fileName);
if (dataBase.Keys.Contains(partNum))
{
dataBase[partNum].Add(path);
}
else
{
dataBase.Add(partNum, new CommaDelimitedStringCollection { path });
}
}
}
private string BuildPartsDbStr()
{
var sb = new StringBuilder();
var db = from x in dataBase orderby x.Key select x;
foreach (var record in db)
{
sb.AppendLine(string.Format("{0}: {1}", record.Key, record.Value));
}
return sb.ToString();
}
private Dictionary<int, CommaDelimitedStringCollection> GetDatabase()
{
var contents = GetFileContents(DATABASE_PATH);
var commaStr = new CommaDelimitedStringCollection();
var db = new Dictionary<int, CommaDelimitedStringCollection>();
var id = 0;
var collection = new CommaDelimitedStringCollection();
for (var i = 0; i < commaStr.Count; i++ )
{
var str = commaStr[i];
if (str.Contains(":"))
{
collection.Add(str.Split(':')[1]);
if (i > 0) db.Add(id, collection);
collection = new CommaDelimitedStringCollection();
id = int.Parse(str.Split(':')[0]);
}
else
{
collection.Add(str);
}
}
return db;
}
private List<int> GetPartNumbers(string filePath)
{
var contents = GetFileContents(filePath);
var commaStr = new CommaDelimitedStringCollection();
var result = new List<int>();
commaStr.AddRange(contents.Split(','));
for(var i = 7; i < commaStr.Count; i += 15)
{
result.Add(int.Parse(commaStr[i].Replace("\"", string.Empty)));
}
return result;
}
private string GetFileContents(string path)
{
using (var stream = new StreamReader(path))
{
//yes I know this is evil - I don't have all night :P
return stream.ReadToEnd();
}
}
private void WriteFileContents(string path, string contents)
{
using (var stream = new StreamWriter(path, false))
{
stream.Write(contents);
stream.Flush();
}
}
}
}