Question

我正在寻找以下问题的答案

我有一个包含3个以下表格的数据库：

TB-001_ISB
TB-002_ISDB
TI-003_ISBDB

表TB-001_ISB下的数据是

ISB_No                  ISB_Ad
121XS9060301            ANKARA CANKAYA
122CV9061501            ANKARA YILDIZ
123BN9062081            ANKARA KIZILAY
124GH8709034            ANKARA MAMAK

TB-002_ISDB下的数据是

ISDB_ID                ISDB_Sit
F-10-01-MM             Factory Production
F-20-01-MG             Factory Quality
F-30-01-FM             Site

TI-003_ISBDB下的数据

ISBDB_No              ISBDB_ISDB_ID         ISBDB_Pers          ISBDB_Date
121XS9060301          F-10-01-MM            1234                01.01.2010
121XS9060301          F-20-01-MG            1234                02.01.2010
121XS9060301          F-30-01-FM            4321                03.01.2010
121XS9060301          F-20-01-MG            6785                04.01.2010
122CV9061501          F-10-01-MM            1234                01.03.2010
122CV9061501          F-20-01-MG            1234                02.03.2010
123BN9062081          F-20-01-MG            4321                03.10.2010
123BN9062081          F-30-01-FM            6785                04.10.2010

我需要一个查询来获得以下输出：

ISBDB_No              ISB_Ad              ISDB_Sit         ISBDB_Pers          ISBDB_Date
121XS9060301          ANKARA CANKAYA      Factory Quality  6785                04.01.2010
122CV9061501          ANKARA YILDIZ       Factory Quality  1234                02.03.2010
123BN9062081          ANKARA KIZILAY      Site             6785                04.10.2010

基本上，我希望结果按ISBDB_Date排序并取最大值（ISBDB_Date）为此，我写了以下查询

SELECT  [ISB_No], [ISB_Ad], [ISDB_Sit], [ISBDB_Pers], 
(SELECT (Max([ISBDB_Date]) 
FROM [TI-003_ISBDB]
GROUP BY [ISBDB_No])

FROM  (([TB-001_ISB] INNER JOIN [TI-003_ISBDB] ON [ISB_No]=[ISBDB_No]) 
INNER JOIN   [TB-002_ISDB] ON [ISDB_ID]=[ISBDB_ISDB_ID])

但是，此查询存在问题。有谁能够帮我？所有的努力都受到高度赞赏......

Answer 1

尝试这样的事情：

WITH CTE AS
(
    SELECT *, ROW_NUMBER() OVER(PARTITION BY [ISBDB_No] ORDER BY [ISBDB_Date] DESC) Corr
    FROM [TI-003_ISBDB]
)
SELECT B.*, [ISB_Ad], [ISDB_Sit]
FROM [TB-001_ISB] A
INNER JOIN (SELECT * FROM CTE WHERE corr = 1) B
ON A.[ISB_No] = B.[ISBDB_No]
INNER JOIN [TB-002_ISDB] C
ON C.[ISDB_ID] = B.[ISBDB_ISDB_ID]

Answer 2

SELECT
    ISB_No
    ,ISB_Ad
    ,ISDB_Sit
    ,ISBDB_Pers
    ,ISBDB_Date
FROM  [TB-001_ISB] AS isb
INNER JOIN [TI-003_ISBDB] AS isdbd ON isb.ISB_No=isdbd.ISBDB_No 
INNER JOIN   [TB-002_ISDB] AS isdb ON isdb.ISDB_ID=isdbd.ISBDB_ISDB_ID
WHERE isdbd.ISBDB_Date = (select MAX(isdbd1.ISBDB_Date) FROM [TI-003_ISBDB] AS isdbd1
    WHERE isdbd.ISBDB_No = isdbd1.ISBDB_No)
ORDER BY isdbd.ISBDB_Date DESC

在SQL Server 2005中使用MAX

2 个答案: