请告诉我下面这段代码的错误。我尝试了很多次,但我仍然收到错误:“应用程序demojson_google意外停止”并没有显示所有内容。这是我的代码:
课程结果
package com.javacode.android.json.model;
import com.google.gson.annotations.SerializedName;
public class Result {
@SerializedName("GsearchResultClass")
public String GsearchResultClass;
@SerializedName("viewportmode")
public String viewportmode;
@SerializedName("listingType")
public String listingType;
@SerializedName("lat")
public String lat;
@SerializedName("lng")
public String lng;
@SerializedName("title")
public String title;
}
Class SearchResponse
package com.javacode.android.json.model;
import java.util.List;
public class SearchResponse {
public List<Result> results;
}
GoogleSearchActivity类
package com.javacode.android.json;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.Reader;
import java.util.List;
import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.HttpStatus;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.impl.client.DefaultHttpClient;
import com.google.gson.Gson;
import com.javacode.android.json.model.R;
import com.javacode.android.json.model.Result;
import com.javacode.android.json.model.SearchResponse;
import android.app.Activity;
import android.os.Bundle;
import android.util.Log;
import android.widget.Toast;
public class GoogleSearchActivity extends Activity {
/** Called when the activity is first created. */
String url = "ajax.googleapis.com/ajax/services/search/local?v=1.0&q=train&sll=50.00001,-5.00001";
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
InputStream source = retrieveStream(url);
Gson gson = new Gson();
Reader reader = new InputStreamReader(source);
SearchResponse response = gson.fromJson(reader, SearchResponse.class);
List<Result> results = response.results;
for (Result result : results) {
Toast.makeText(this, result.title, Toast.LENGTH_SHORT).show();
}
}
private InputStream retrieveStream(String url) {
DefaultHttpClient client = new DefaultHttpClient();
HttpGet getRequest = new HttpGet(url);
try {
HttpResponse getResponse = client.execute(getRequest);
final int statusCode = getResponse.getStatusLine().getStatusCode();
if (statusCode != HttpStatus.SC_OK) {
Log.w(getClass().getSimpleName(),
"Error " + statusCode + " for URL " + url);
return null;
}
HttpEntity getResponseEntity = getResponse.getEntity();
return getResponseEntity.getContent();
}
catch (IOException e) {
getRequest.abort();
Log.w(getClass().getSimpleName(), "Error for URL " + url, e);
}
return null;
}
}
谢谢!
答案 0 :(得分:0)
我的,你有很多空的。第一个null来自retrieveStream。试试这个:
InputStream is = null;
DefaultHttpClient client = new DefaultHttpClient();
HttpGet getRequest = new HttpGet(url);
try {
HttpResponse getResponse = client.execute(getRequest);
final int statusCode = getResponse.getStatusLine().getStatusCode();
if (statusCode != HttpStatus.SC_OK) {
Log.w(getClass().getSimpleName(),
"Error " + statusCode + " for URL " + url);
}
else
{
HttpEntity getResponseEntity = getResponse.getEntity();
is = getResponseEntity.getContent();
}
}
catch (IOException e) {
getRequest.abort();
Log.w(getClass().getSimpleName(), "Error for URL " + url, e);
}
return is;
确保您在Manifest中拥有使用许可INTERNET。
Afler所有的SearchResponse也是null。 我没有使用gson。为什么不考虑使用旧的这个:
HttpGet httpget = new HttpGet(url);
HttpResponse response;
response = httpclient.execute(httpget);
HttpEntity entity = response.getEntity();
if (entity != null) {
InputStream instream = entity.getContent();
gpResult = new GPResult();
JSONObject json=new JSONObject(
convertStreamToString(instream
));
//the rest of JSON object processing
干杯。