Question

我有EditText "text = 0.00"。当我按下数字3时，它应该是0.03，第二次按下数字5时，文本应该是0.35。 35.0，35.09就像这样。 EditText最初的值为0.00。

这些都是使用相同的EditText完成的。

我如何实现这一目标？我尝试将addTextChangedListener()与TextWatcher()一起使用。

Answer 1

你也可以试试这个：

EditText searchTo = (EditText)findViewById(R.id.medittext);
searchTo.addTextChangedListener(new TextWatcher() {
    @Override
    public void afterTextChanged(Editable s) {
        // TODO Auto-generated method stub
    }

    @Override
    public void beforeTextChanged(CharSequence s, int start, int count, int after) {
        // TODO Auto-generated method stub
    }

    @Override
    public void onTextChanged(CharSequence s, int start, int before, int count) {
        doSomething();
    } 
});

Answer 2

您选择了正确的方法。您必须使用TextWatcher扩展该类并覆盖afterTextChanged()，beforeTextChanged()，onTextChanged()。

您必须使用afterTextChanged()方法编写所需的逻辑，以实现您所需的功能。

Answer 3

在这里，我写了类似于你需要的东西：

    inputBoxNumberEt.setText(".     ");
    inputBoxNumberEt.setSelection(inputBoxNumberEt.getText().length());
    inputBoxNumberEt.addTextChangedListener(new TextWatcher() {

        boolean ignoreChange = false;

        @Override
        public void afterTextChanged(Editable s) {
        }

        @Override
        public void beforeTextChanged(CharSequence s, int start,
                                      int count, int after) {
        }

        @Override
        public void onTextChanged(CharSequence s, int start,
                                  int before, int count) {
            if (!ignoreChange) {
                String string = s.toString();
                string = string.replace(".", "");
                string = string.replace(" ", "");
                if (string.length() == 0)
                    string = ".     ";
                else if (string.length() == 1)
                    string = ".  " + string;
                else if (string.length() == 2)
                    string = "." + string;
                else if (string.length() > 2)
                    string = string.substring(0, string.length() - 2) + "." + string.substring(string.length() - 2, string.length());
                ignoreChange = true;
                inputBoxNumberEt.setText(string);
                inputBoxNumberEt.setSelection(inputBoxNumberEt.getText().length());
                ignoreChange = false;
            }
        }
    });

Answer 4

将逻辑放入

afterTextChanged(Editable s) {
    string str = s.toString()
    // use the string str
}

documentation on TextWatcher

Answer 5

更改文字；

multipleLine.addTextChangedListener(new TextWatcher() {
        @Override
        public void beforeTextChanged(CharSequence s, int start, int count, int after) {

        }

        @Override
        public void onTextChanged(CharSequence s, int start, int before, int count) {
            MainActivity.myArray.set(pickId,String.valueOf(s));
            MainActivity.myAdapt.notifyDataSetChanged();
        }

        @Override
        public void afterTextChanged(Editable s) {

        }

Answer 6

在Kotlin中，使用设置Android EditText侦听器，

 const axios = require('axios');
    const fs = require('fs');
    var https = require('https');
    
    const httpagent = new https.Agent({
        rejectUnauthorized: false,
        ca: fs.readFileSync('path to rootCA.cer'),

    })
    //sslrootCAs.inject();
    axios.get(
        `https://REST_API_URL`, { httpagent }
    )

Answer 7

这是可用的 Kotlin 版本。

  yourEditText.addTextChangedListener(object: TextWatcher {
    override fun afterTextChanged(s: Editable?) {
      // TODO Auto-generated method stub
    }

    override fun beforeTextChanged(s: CharSequence?, start: Int, count: Int, after: Int) {
      // TODO Auto-generated method stub
    }

    override fun onTextChanged(s: CharSequence?, start: Int, before: Int, count: Int) {
      doSomething()
    }
  })

当我按下号码时如何使用EditText onTextChanged事件？

7 个答案: