Question

我想通过引用发送一个对象。该对象代表一个类

[test.php的]

$car= new Car();
$car->l=1000;

$car2 = new Car2();
$car2->method($car);

[php_cod.cc]

PHP_METHOD(Car2, method)
{
    Car2 *car;
    Car obj11;
    zend_class_entry ce2;

     if (zend_parse_parameters(ZEND_NUM_ARGS() TSRMLS_CC, "o", &obj11) == FAILURE) {
        RETURN_NULL();
    }



    car2_object *obj = (car2_object *)zend_object_store_get_object(
        getThis() TSRMLS_CC);
    car2 = obj->car2;
    if (car2 != NULL) {
        //cout<<"in car 2 ref"<<endl;

        //car2->reference(s);
        (car2->method(obj11));
    }

}

[test.cc]

void Car2::method(Car &carr)
{
    cout<<"IN THE REFERENCE CLASS"<<carr.l<<endl; 

}

我哪里错了？谢谢！欣赏

当我运行php test.php时，值vor carr.l等于 155160836.为什么？我哪里错了

Answer 1

在代码的php部分，obj11是一个未初始化的指针，它被传递给Car2 :: method（(car2->method(*obj11));）。所以 -

 cout<<"IN THE REFERENCE CLASS"<<carr.l<<endl; 
 // carr is a garbage reference and is causing the segmentation fault

php扩展值不正确打印为什么？

1 个答案: