Question

我有这样的查询：

select d.id from days as d JOIN tv_programs AS t ON (d.tv_program_id = t.id) WHERE d.date=? AND t.type=0 ORDER BY d.date, t.date DESC OFFSET 1;

它返回1个选定日期（类型日期）的数据，但我想从startDate到endDate获取值，例如，我想使用一个类似的查询来执行此操作：

select d.id from days as d JOIN tv_programs AS t ON (d.tv_program_id = t.id) WHERE d.date='2011-09-01' AND t.type=0 ORDER BY d.date, t.date DESC OFFSET 1;
select d.id from days as d JOIN tv_programs AS t ON (d.tv_program_id = t.id) WHERE d.date='2011-09-02' AND t.type=0 ORDER BY d.date, t.date DESC OFFSET 1;
select d.id from days as d JOIN tv_programs AS t ON (d.tv_program_id = t.id) WHERE d.date='2011-09-03' AND t.type=0 ORDER BY d.date, t.date DESC OFFSET 1;

有可能吗？

Answer 1

... where d.date between '2011-09-01' and '2011-09-04'应该有用。

如何在postgresql查询中选择日期间隔？

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