如何从字符串中删除字符?例如:"My name @is ,Wan.;'; Wan"
。
我想从该字符串中删除字符'@', ',', '.', ';', '\''
,使其变为"My name is Wan Wan"
答案 0 :(得分:157)
var str = "My name @is ,Wan.;'; Wan";
var charsToRemove = new string[] { "@", ",", ".", ";", "'" };
foreach (var c in charsToRemove)
{
str = str.Replace(c, string.Empty);
}
但如果你想删除所有非字母字符,我可能会建议另一种方法
var str = "My name @is ,Wan.;'; Wan";
str = new string((from c in str
where char.IsWhiteSpace(c) || char.IsLetterOrDigit(c)
select c
).ToArray());
答案 1 :(得分:56)
简单:
String.Join("", "My name @is ,Wan.;'; Wan".Split('@', ',' ,'.' ,';', '\''));
答案 2 :(得分:54)
听起来像RegEx的理想应用程序 - 一个专为快速文本操作而设计的引擎。在这种情况下:
Regex.Replace("He\"ll,o Wo'r.ld", "[@,\\.\";'\\\\]", string.Empty)
答案 3 :(得分:18)
对您的问题不太具体,可以通过白名单在正则表达式中列出可接受的字符,从字符串(空格除外)中删除所有标点符号:
string dirty = "My name @is ,Wan.;'; Wan";
// only space, capital A-Z, lowercase a-z, and digits 0-9 are allowed in the string
string clean = Regex.Replace(dirty, "[^A-Za-z0-9 ]", "");
请注意,在9之后有一个空格,以免从句子中删除空格。第三个参数是一个空字符串,用于替换不属于正则表达式的任何子字符串。
答案 4 :(得分:16)
string x = "My name @is ,Wan.;'; Wan";
string modifiedString = x.Replace("@", "").Replace(",", "").Replace(".", "").Replace(";", "").Replace("'", "");
答案 5 :(得分:9)
比较各种建议(以及在单字符替换与目标的各种大小和位置的情况下进行比较)。
在这种特殊情况下,拆分目标并加入替换(在这种情况下,空字符串)是最快的至少3倍。最终,性能根据替换的数量而有所不同,其中替换是在源中,以及源的大小。 #ymmv
(完整结果here)
| Test | Compare | Elapsed |
|---------------------------|---------|--------------------------------------------------------------------|
| SplitJoin | 1.00x | 29023 ticks elapsed (2.9023 ms) [in 10K reps, 0.00029023 ms per] |
| Replace | 2.77x | 80295 ticks elapsed (8.0295 ms) [in 10K reps, 0.00080295 ms per] |
| RegexCompiled | 5.27x | 152869 ticks elapsed (15.2869 ms) [in 10K reps, 0.00152869 ms per] |
| LinqSplit | 5.43x | 157580 ticks elapsed (15.758 ms) [in 10K reps, 0.0015758 ms per] |
| Regex, Uncompiled | 5.85x | 169667 ticks elapsed (16.9667 ms) [in 10K reps, 0.00169667 ms per] |
| Regex | 6.81x | 197551 ticks elapsed (19.7551 ms) [in 10K reps, 0.00197551 ms per] |
| RegexCompiled Insensitive | 7.33x | 212789 ticks elapsed (21.2789 ms) [in 10K reps, 0.00212789 ms per] |
| Regex Insentive | 7.52x | 218164 ticks elapsed (21.8164 ms) [in 10K reps, 0.00218164 ms per] |
(注意:Perf
和Vs
为timing extensions I wrote)
void test(string title, string sample, string target, string replacement) {
var targets = target.ToCharArray();
var tox = "[" + target + "]";
var x = new Regex(tox);
var xc = new Regex(tox, RegexOptions.Compiled);
var xci = new Regex(tox, RegexOptions.Compiled | RegexOptions.IgnoreCase);
// no, don't dump the results
var p = new Perf/*<string>*/();
p.Add(string.Join(" ", title, "Replace"), n => targets.Aggregate(sample, (res, curr) => res.Replace(new string(curr, 1), replacement)));
p.Add(string.Join(" ", title, "SplitJoin"), n => String.Join(replacement, sample.Split(targets)));
p.Add(string.Join(" ", title, "LinqSplit"), n => String.Concat(sample.Select(c => targets.Contains(c) ? replacement : new string(c, 1))));
p.Add(string.Join(" ", title, "Regex"), n => Regex.Replace(sample, tox, replacement));
p.Add(string.Join(" ", title, "Regex Insentive"), n => Regex.Replace(sample, tox, replacement, RegexOptions.IgnoreCase));
p.Add(string.Join(" ", title, "Regex, Uncompiled"), n => x.Replace(sample, replacement));
p.Add(string.Join(" ", title, "RegexCompiled"), n => xc.Replace(sample, replacement));
p.Add(string.Join(" ", title, "RegexCompiled Insensitive"), n => xci.Replace(sample, replacement));
var trunc = 40;
var header = sample.Length > trunc ? sample.Substring(0, trunc) + "..." : sample;
p.Vs(header);
}
void Main()
{
// also see https://stackoverflow.com/questions/7411438/remove-characters-from-c-sharp-string
"Control".Perf(n => { var s = "*"; });
var text = "My name @is ,Wan.;'; Wan";
var clean = new[] { '@', ',', '.', ';', '\'' };
test("stackoverflow", text, string.Concat(clean), string.Empty);
var target = "o";
var f = "x";
var replacement = "1";
var fillers = new Dictionary<string, string> {
{ "short", new String(f[0], 10) },
{ "med", new String(f[0], 300) },
{ "long", new String(f[0], 1000) },
{ "huge", new String(f[0], 10000) }
};
var formats = new Dictionary<string, string> {
{ "start", "{0}{1}{1}" },
{ "middle", "{1}{0}{1}" },
{ "end", "{1}{1}{0}" }
};
foreach(var filler in fillers)
foreach(var format in formats) {
var title = string.Join("-", filler.Key, format.Key);
var sample = string.Format(format.Value, target, filler.Value);
test(title, sample, target, replacement);
}
}
答案 6 :(得分:7)
最简单的方法是使用String.Replace
:
String s = string.Replace("StringToReplace", "NewString");
答案 7 :(得分:6)
另一个简单的解决方案:
var forbiddenChars = @"@,.;'".ToCharArray();
var dirty = "My name @is ,Wan.;'; Wan";
var clean = new string(dirty.Where(c => !forbiddenChars.Contains(c)).ToArray());
答案 8 :(得分:5)
new List<string> { "@", ",", ".", ";", "'" }.ForEach(m => str = str.Replace(m, ""));
答案 9 :(得分:4)
字符串只是一个字符数组,所以使用Linq进行替换(类似于上面的Albin,除了使用linq contains语句进行替换):
var resultString = new string(
(from ch in "My name @is ,Wan.;'; Wan"
where ! @"@,.;\'".Contains(ch)
select ch).ToArray());
第一个字符串是替换chars in和的字符串 second是包含字符的简单字符串
答案 10 :(得分:2)
似乎最简单的方法是组合LINQ和string.Concat
:
var input = @"My name @is ,Wan.;'; Wan";
var chrs = new[] {'@', ',', '.', ';', '\''};
var result = string.Concat(input.Where(c => !chrs.Contains(c)));
// => result = "My name is Wan Wan"
请参阅C# demo。请注意,string.Concat
是string.Join("", ...)
的快捷方式。
请注意,使用正则表达式删除单个已知字符仍然可以动态构建,尽管相信正则表达式较慢。但是,这里有一种构建这样一个动态正则表达式的方法(你需要的只是一个字符类):
var pattern = $"[{Regex.Escape(new string(chrs))}]+";
var result = Regex.Replace(input, pattern, string.Empty);
见another C# demo。正则表达式看起来像[@,\.;']+
(匹配一个或多个(+
)连续出现的@
,,
,.
,;
或{ {1}}字符)其中点不必转义,但必须使用'
来转义必须转义的其他字符,例如Regex.Escape
,\
,{{1或者^
,它在你无法预测的角色类中的位置。
答案 11 :(得分:2)
根据@drzaus的性能数据,这是使用最快算法的扩展方法。
public static class StringEx
{
public static string RemoveCharacters(this string s, params char[] unwantedCharacters)
=> s == null ? null : string.Join(string.Empty, s.Split(unwantedCharacters));
}
用法
var name = "edward woodward!";
var removeDs = name.RemoveCharacters('d', '!');
Assert.Equal("ewar woowar", removeDs); // old joke
答案 12 :(得分:2)
这里有很多好的答案,这里是我的补充以及可用于帮助测试正确性的几个单元测试,我的解决方案类似于上面的@Rianne,但使用ISet为替换字符提供O(1)查找时间(也类似于@Albin Sunnanbo的Linq解决方案)。
using System;
using System.Collections.Generic;
using System.Linq;
/// <summary>
/// Returns a string with the specified characters removed.
/// </summary>
/// <param name="source">The string to filter.</param>
/// <param name="removeCharacters">The characters to remove.</param>
/// <returns>A new <see cref="System.String"/> with the specified characters removed.</returns>
public static string Remove(this string source, IEnumerable<char> removeCharacters)
{
if (source == null)
{
throw new ArgumentNullException("source");
}
if (removeCharacters == null)
{
throw new ArgumentNullException("removeCharacters");
}
// First see if we were given a collection that supports ISet
ISet<char> replaceChars = removeCharacters as ISet<char>;
if (replaceChars == null)
{
replaceChars = new HashSet<char>(removeCharacters);
}
IEnumerable<char> filtered = source.Where(currentChar => !replaceChars.Contains(currentChar));
return new string(filtered.ToArray());
}
NUnit(2.6+)测试
using System;
using System.Collections;
using System.Collections.Generic;
using NUnit.Framework;
[TestFixture]
public class StringExtensionMethodsTests
{
[TestCaseSource(typeof(StringExtensionMethodsTests_Remove_Tests))]
public void Remove(string targetString, IEnumerable<char> removeCharacters, string expected)
{
string actual = StringExtensionMethods.Remove(targetString, removeCharacters);
Assert.That(actual, Is.EqualTo(expected));
}
[TestCaseSource(typeof(StringExtensionMethodsTests_Remove_ParameterValidation_Tests))]
public void Remove_ParameterValidation(string targetString, IEnumerable<char> removeCharacters)
{
Assert.Throws<ArgumentNullException>(() => StringExtensionMethods.Remove(targetString, removeCharacters));
}
}
internal class StringExtensionMethodsTests_Remove_Tests : IEnumerable
{
public IEnumerator GetEnumerator()
{
yield return new TestCaseData("My name @is ,Wan.;'; Wan", new char[] { '@', ',', '.', ';', '\'' }, "My name is Wan Wan").SetName("StringUsingCharArray");
yield return new TestCaseData("My name @is ,Wan.;'; Wan", new HashSet<char> { '@', ',', '.', ';', '\'' }, "My name is Wan Wan").SetName("StringUsingISetCollection");
yield return new TestCaseData(string.Empty, new char[1], string.Empty).SetName("EmptyStringNoReplacementCharactersYieldsEmptyString");
yield return new TestCaseData(string.Empty, new char[] { 'A', 'B', 'C' }, string.Empty).SetName("EmptyStringReplacementCharsYieldsEmptyString");
yield return new TestCaseData("No replacement characters", new char[1], "No replacement characters").SetName("StringNoReplacementCharactersYieldsString");
yield return new TestCaseData("No characters will be replaced", new char[] { 'Z' }, "No characters will be replaced").SetName("StringNonExistantReplacementCharactersYieldsString");
yield return new TestCaseData("AaBbCc", new char[] { 'a', 'C' }, "ABbc").SetName("CaseSensitivityReplacements");
yield return new TestCaseData("ABC", new char[] { 'A', 'B', 'C' }, string.Empty).SetName("AllCharactersRemoved");
yield return new TestCaseData("AABBBBBBCC", new char[] { 'A', 'B', 'C' }, string.Empty).SetName("AllCharactersRemovedMultiple");
yield return new TestCaseData("Test That They Didn't Attempt To Use .Except() which returns distinct characters", new char[] { '(', ')' }, "Test That They Didn't Attempt To Use .Except which returns distinct characters").SetName("ValidateTheStringIsNotJustDistinctCharacters");
}
}
internal class StringExtensionMethodsTests_Remove_ParameterValidation_Tests : IEnumerable
{
public IEnumerator GetEnumerator()
{
yield return new TestCaseData(null, null);
yield return new TestCaseData("valid string", null);
yield return new TestCaseData(null, new char[1]);
}
}
答案 13 :(得分:2)
我不妨把它扔出去。
进行扩展以从字符串中删除字符:
public static string RemoveChars(this string input, params char[] chars)
{
var sb = new StringBuilder();
for (int i = 0; i < input.Length; i++)
{
if (!chars.Contains(input[i]))
sb.Append(input[i]);
}
return sb.ToString();
}
它可以这样使用:
string str = "My name @is ,Wan.;'; Wan";
string cleanedUpString = str.RemoveChars('@', ',', '.', ';', '\'');
或者就像这样:
string str = "My name @is ,Wan.;'; Wan".RemoveChars('@', ',', '.', ';', '\'');
答案 14 :(得分:1)
旧学校复制/踩踏:
private static string RemoveDirtyCharsFromString(string in_string)
{
int index = 0;
int removed = 0;
byte[] in_array = Encoding.UTF8.GetBytes(in_string);
foreach (byte element in in_array)
{
if ((element == ' ') ||
(element == '-') ||
(element == ':'))
{
removed++;
}
else
{
in_array[index] = element;
index++;
}
}
Array.Resize<byte>(ref in_array, (in_array.Length - removed));
return(System.Text.Encoding.UTF8.GetString(in_array, 0, in_array.Length));
}
不确定效率w.r.t.其他方法(即在C#执行中作为副作用发生的所有函数调用和实例化的开销)。
答案 15 :(得分:1)
我使用扩展方法和字符串数组,我认为string[]
比char[]
更有用,因为char也可以是字符串:
public static class Helper
{
public static string RemoverStrs(this string str, string[] removeStrs)
{
foreach (var removeStr in removeStrs)
str = str.Replace(removeStr, "");
return str;
}
}
然后你可以在任何地方使用它:
string myname = "My name @is ,Wan.;'; Wan";
string result = myname.RemoveStrs(new[]{ "@", ",", ".", ";", "\\"});
答案 16 :(得分:1)
我需要从XML文件中删除特殊字符。这是我的方法。 char.ToString()是这段代码中的英雄。
string item = "<item type="line" />"
char DC4 = (char)0x14;
string fixed = item.Replace(DC4.ToString(), string.Empty);
答案 17 :(得分:1)
new[] { ',', '.', ';', '\'', '@' }
.Aggregate("My name @is ,Wan.;'; Wan", (s, c) => s.Replace(c.ToString(), string.Empty));
答案 18 :(得分:0)
这是我写的一种方法,该方法略有不同。我没有指定要删除的字符,而是告诉我的方法我要保留的字符-它将删除所有其他字符。
在OP的示例中,他只想保留字母字符和空格。这是调用我的方法的样子(C# demo):
var str = "My name @is ,Wan.;'; Wan";
// "My name is Wan Wan"
var result = RemoveExcept(str, alphas: true, spaces: true);
这是我的方法:
/// <summary>
/// Returns a copy of the original string containing only the set of whitelisted characters.
/// </summary>
/// <param name="value">The string that will be copied and scrubbed.</param>
/// <param name="alphas">If true, all alphabetical characters (a-zA-Z) will be preserved; otherwise, they will be removed.</param>
/// <param name="numerics">If true, all alphabetical characters (a-zA-Z) will be preserved; otherwise, they will be removed.</param>
/// <param name="dashes">If true, all alphabetical characters (a-zA-Z) will be preserved; otherwise, they will be removed.</param>
/// <param name="underlines">If true, all alphabetical characters (a-zA-Z) will be preserved; otherwise, they will be removed.</param>
/// <param name="spaces">If true, all alphabetical characters (a-zA-Z) will be preserved; otherwise, they will be removed.</param>
/// <param name="periods">If true, all decimal characters (".") will be preserved; otherwise, they will be removed.</param>
public static string RemoveExcept(string value, bool alphas = false, bool numerics = false, bool dashes = false, bool underlines = false, bool spaces = false, bool periods = false) {
if (string.IsNullOrWhiteSpace(value)) return value;
if (new[] { alphas, numerics, dashes, underlines, spaces, periods }.All(x => x == false)) return value;
var whitelistChars = new HashSet<char>(string.Concat(
alphas ? "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ" : "",
numerics ? "01234567890" : "",
dashes ? "-" : "",
underlines ? "_" : "",
periods ? "." : "",
spaces ? " " : ""
).ToCharArray());
var scrubbedValue = value.Aggregate(new StringBuilder(), (sb, @char) => {
if (whitelistChars.Contains(@char)) sb.Append(@char);
return sb;
}).ToString();
return scrubbedValue;
}
答案 19 :(得分:0)
在相同情况下通常使用的一种强大的方法:
private string Normalize(string text)
{
return string.Join("",
from ch in text
where char.IsLetterOrDigit(ch) || char.IsWhiteSpace(ch)
select ch);
}
享受...
答案 20 :(得分:0)
这是删除文件名中无效字符的好方法:
string.Join(string.Empty, filename.Split(System.IO.Path.GetInvalidFileNameChars()));
答案 21 :(得分:0)
您可以删除非字符。
使用 array
和 string[] non_character = (new string[] {"@", ",", ".", ";", "'"});
string text = "My name @is ,Wan.;'; Wan";
string final_str = "";
foreach (string str in non_character)
{
final_str = text.replace(str, "");
}
Console.WriteLine(final_str);
。
不能使用单引号,因为这是一个字符串。
class HelloCodiva {
public static void main(String[] args) {
System.out.println("Formatted: "
+ bold("bold") + " " + italic("italic") + " " + bold(italic("both")));
}
static CharSequence bold(CharSequence cs) {
return trans(cs, 0x1D400, 0x1D41A);
}
static CharSequence italic(CharSequence cs) {
return trans(cs, 0x1D434, 0x1D44e);
}
static CharSequence trans(CharSequence cs, int upper, int lower) {
return cs.codePoints()
.map(cp -> cp >= 'A' && cp <= 'Z'? cp + upper - 'A':
cp >= 'a' && cp <= 'z'? cp + lower - 'a':
cp >= 0x1D400 && cp <= 0x1D433? cp + 104:
cp >= 0x1D434 && cp <= 0x1D467? cp + 52:
cp)
.collect(StringBuilder::new,
StringBuilder::appendCodePoint, StringBuilder::append);
}
}
这很简单...
答案 22 :(得分:0)
如果要删除所有空格和特殊字符
var input = Console.ReadLine();
foreach (var item in input)
{
var limit = ((int)item);
if (limit>=65 && limit<=90 || limit>=97 && limit<= 122)
{
Console.Write(item);
}
}
答案 23 :(得分:-2)
如果要替换'['']',可以尝试以下操作:
foreach(var c in "[ \"]")
{
string s = c + "";
inputText = inputText.Replace(s, "");
}