我在Excel 2007中使用颜色比例进行条件格式化,并且我很难找到条件格式化单元格的填充颜色代码。我知道Interior.Color返回默认颜色值,但在使用条件格式时没有用。我很中庸地意识到这有多么艰难。
谢谢。
答案 0 :(得分:7)
您可以像这样访问成帧条件的内部颜色(不是单元格当前的颜色),假设这是应用于单元格的第一个条件:
Range("A1").FormatConditions(1).interior.color
这是一个函数,它将返回单元格包含的所有条件格式的颜色代码。如果没有条件,它将不会返回任何内容,如果有条件但没有为它设置颜色,那么它会告诉你“无”。
Function ConditionalColor(ByVal cell As Range)
Dim colors As String
Dim i As Long
For i = 1 To Range(cell.Address).FormatConditions.count
If Range(cell.Address).FormatConditions(i).Interior.Color <> 0 Then
colors = colors & "Condition " & i & ": " & _
Range(cell.Address).FormatConditions(i).Interior.Color & vbLf
Else
colors = colors & "Condition " & i & ": None" & vbLf
End If
Next
If Len(colors) <> 0 Then
colors = Left(colors, Len(colors) - 1)
End If
ConditionalColor = colors
End Function
<强>更新强>: 如果你很好奇(我是),Excel使用的颜色代码实际上是BGR,而不是RGB。因此,如果您想将代码转换为RGB值,可以使用:
Function GetRGB(ByVal cell As range) As String
Dim R As String, G As String
Dim B As String, hexColor As String
hexCode = Hex(cell.Interior.Color)
'Note the order excel uses for hex is BGR.
B = Val("&H" & Mid(hexCode, 1, 2))
G = Val("&H" & Mid(hexCode, 3, 2))
R = Val("&H" & Mid(hexCode, 5, 2))
GetRGB = R & ":" & G & ":" & B
End Function
答案 1 :(得分:6)
嗨您提供的答案无效,因为我使用的是色标,因此它不会返回正常的3个条件值。
经过多次搜索后,我找到了一个有效的解决方法。那就是取数据并将其放入单词然后将其复制回excel,使得范围在单元格中变为真彩色,因此Interior.Color将起作用。我找到了一个已经把它带入VBA的人。如果其他人想要这样做的话,这是link。
答案 2 :(得分:3)
我没有适用于Excel 2007或更低版本的答案,但从Excel 2010开始,您可以使用以下内容(更改范围以适应):
Range("A1").DisplayFormat.Interior.ColorIndex
幸运的是,虽然Excel 2003以后支持我需要它的软件,但实际上我只是在测试过程中需要它,并且测试模块已从生产版本中删除。
答案 3 :(得分:2)
以下代码来自VBAExpress,所有信用都是原作者 - byundt。
可能需要针对excel 2007进行修改。
Function ConditionalColor(rg As Range, FormatType As String) As Long
'Returns the color index (either font or interior) of the first cell in range rg. If no _
conditional format conditions apply, Then returns the regular color of the cell. _
FormatType Is either "Font" Or "Interior"
Dim cel As Range
Dim tmp As Variant
Dim boo As Boolean
Dim frmla As String, frmlaR1C1 As String, frmlaA1 As String
Dim i As Long
'Application.Volatile 'This statement required if Conditional Formatting for rg is determined by the _
value of other cells
Set cel = rg.Cells(1, 1)
Select Case Left(LCase(FormatType), 1)
Case "f" 'Font color
ConditionalColor = cel.Font.ColorIndex
Case Else 'Interior or highlight color
ConditionalColor = cel.Interior.ColorIndex
End Select
If cel.FormatConditions.Count > 0 Then
'On Error Resume Next
With cel.FormatConditions
For i = 1 To .Count 'Loop through the three possible format conditions for each cell
frmla = .Item(i).Formula1
If Left(frmla, 1) = "=" Then 'If "Formula Is", then evaluate if it is True
'Conditional Formatting is interpreted relative to the active cell. _
This cause the wrong results If the formula isn 't restated relative to the cell containing the _
Conditional Formatting--hence the workaround using ConvertFormula twice In a row. _
If the Function were Not called using a worksheet formula, you could just activate the cell instead.
frmlaR1C1 = Application.ConvertFormula(frmla, xlA1, xlR1C1, , ActiveCell)
frmlaA1 = Application.ConvertFormula(frmlaR1C1, xlR1C1, xlA1, xlAbsolute, cel)
boo = Application.Evaluate(frmlaA1)
Else 'If "Value Is", then identify the type of comparison operator and build comparison formula
Select Case .Item(i).Operator
Case xlEqual ' = x
frmla = cel & "=" & .Item(i).Formula1
Case xlNotEqual ' <> x
frmla = cel & "<>" & .Item(i).Formula1
Case xlBetween 'x <= cel <= y
frmla = "AND(" & .Item(i).Formula1 & "<=" & cel & "," & cel & "<=" & .Item(i).Formula2 & ")"
Case xlNotBetween 'x > cel or cel > y
frmla = "OR(" & .Item(i).Formula1 & ">" & cel & "," & cel & ">" & .Item(i).Formula2 & ")"
Case xlLess ' < x
frmla = cel & "<" & .Item(i).Formula1
Case xlLessEqual ' <= x
frmla = cel & "<=" & .Item(i).Formula1
Case xlGreater ' > x
frmla = cel & ">" & .Item(i).Formula1
Case xlGreaterEqual ' >= x
frmla = cel & ">=" & .Item(i).Formula1
End Select
boo = Application.Evaluate(frmla) 'Evaluate the "Value Is" comparison formula
End If
If boo Then 'If this Format Condition is satisfied
On Error Resume Next
Select Case Left(LCase(FormatType), 1)
Case "f" 'Font color
tmp = .Item(i).Font.ColorIndex
Case Else 'Interior or highlight color
tmp = .Item(i).Interior.ColorIndex
End Select
If Err = 0 Then ConditionalColor = tmp
Err.Clear
On Error GoTo 0
Exit For 'Since Format Condition is satisfied, exit the inner loop
End If
Next i
End With
End If
End Function