Question

在我用PHP填充的头文件中：

<script type="text/javascript"> 
var packages = {};
packages[1] = {title:'Pack 1',price:7.50,setup:0.00,template:0};
packages[2] = {title:'Pack 2',price:12.00,setup:0.00,template:0};
packages[3] = {title:'Pack 3',price:25.00,setup:75.00,template:1};
var templates = {};
templates[4] = {title:'Template 1'};
templates[5] = {title:'Template 2'};
templates[6] = {title:'Template 3'};
</script>    

<script type="text/javascript" src="/include/jscript/form.inc.js"></script>

现在在form.inc.js中我想要vars包的内容。所以喜欢：

function updatePrices(){
    var package_price = 0;
    var setup_price = 0;

    var package = $_2('#package_select').val();

    package_price += packages[package].price;
    setup_price += packages[package].setup;

    $_2(".package_price").html("&pound;"+package_price);
    $_2(".setup_price").html("&pound;"+setup_price);
    $_2(".total_price").html("&pound;"+(package_price+setup_price));
}

你在这里看到：package [package] .price包[1] .price并且应该显示7.50，但我不认为var包正在通过！

任何帮助都会很棒，谢谢

Answer 1

您的脚本未运行，因为它中包含语法错误：

var packages = {};
packages[1] = {title:'Book'In',price:7.50,setup:0.00,template:0};
/intake/:21SyntaxError: Parse error
packages[2] = {title:'Book'In Plus',price:12.00,setup:0.00,template:0};
packages[3] = {title:'Full Monty',price:25.00,setup:75.00,template:1};
var templates = {};
templates[4] = {title:'Template 1'};
templates[5] = {title:'Template 2'};
templates[6] = {title:'Template 3'};

请注意，您使用单引号标记标题字符串，但其中两个标题中包含单引号。你需要用斜杠来转义单引号，如下所示：

packages[1] = {title: 'Book\'In',price:7.50,setup:0.00,template:0};

请查看浏览器的JavaScript /错误控制台。它会为你做奇迹= D

Answer 2

看起来你的包和模板变量是对象，我想你想要一个数组：

<script type="text/javascript"> 
var packages = [];  //square brackets instead of curly brackets create new arrays

packages[1] = {title:'Pack 1',price:7.50,setup:0.00,template:0};
packages[2] = {title:'Pack 2',price:12.00,setup:0.00,template:0};
packages[3] = {title:'Pack 3',price:25.00,setup:75.00,template:1};

var templates = []; //square brackets instead of curly brackets create new arrays

templates[4] = {title:'Template 1'};
templates[5] = {title:'Template 2'};
templates[6] = {title:'Template 3'};
</script>

JS文件外的JQuery vars

2 个答案: