TSQL - 选择具有较高计数的行，当count相同时，选择具有较高id值的行

Question

HELP !!!我很难过，并尝试了几个选项无济于事...... 我需要为每个Pub_id返回一行，并且返回的行应该是具有更高Count的行，并且当有多个具有最高计数的行时，我需要具有更高price_id的行。

我已用这些数据填充了表格......

pub_id, price_id,   count
7,  59431,            5
22, 39964,            4
39, 112831,           3
39, 120715,           2
47, 95359,            2
74, 142825,           5
74, 106688,           5
74, 37514,            1

---

这就是我需要返回的......

pub_id, price_id,   count
7,  59431,            5
22, 39964,            4
39, 112831,           3
47, 95359,            2
74, 142825,           5

Answer 1

;WITH T
     AS (SELECT *,
                ROW_NUMBER() OVER (PARTITION BY pub_id 
                               ORDER BY [count] DESC, price_id DESC) AS rn
         FROM   your_table)
SELECT pub_id,
       [count],
       price_id
FROM   T  
WHERE rn=1

Answer 2

你想要这样的东西

select pub_id,
       Count,
       Price_Id
from   (select Pub_id,
               max(count),
               Price_Id
        from   table_name
        group  by Pub_id) der_tab
group  by Pub_id,
          Count
having Price_id = max(price_Id)