嗨朋友们...我正在使用正则表达式,所以我得到字符串,但有双引号和斜线,但我不想要那个。我想要字符串值没有斜杠和双引号。我试着这个,但没有得到正确的答案。
运行应用[/Users/pradeepyadav/Desktop/RegexKitLiteDemo/Classes/RegexKitLiteDemoAppDelegate.m:108:0 /Users/pradeepyadav/Desktop/RegexKitLiteDemo/Classes/RegexKitLiteDemoAppDelegate.m:108: error: incompatible block pointer types initializing 'void (^)(struct NSString *, NSUInteger, BOOL *)', expected 'void (^)(struct objc_object *, NSUInteger, BOOL *)
后出错
我得到了这个错误行
第二个是:[/Users/pradeepyadav/Desktop/RegexKitLiteDemo/Classes/RegexKitLiteDemoAppDelegate.m:105:0 /Users/pradeepyadav/Desktop/RegexKitLiteDemo/Classes/RegexKitLiteDemoAppDelegate.m:105: warning: 'NSString' may not respond to '+stringByTrimmingCharactersInSet:
我收到此错误行[webData length] encoding:NSUTF8StringEncoding];
//NSLog(@"%@",loginStatus);
[connection release];
//
NSString *regexString = @"Stations\\[""(.*)""\\] = new Station\\((.*)new Array\\((.*)\\)\\);"; //@"Stations\\[""(.*)""\\] = new Station\\((.*)\\);"; //@"Stations\[""(.*)""\] = new Station\({[\,,2}(.*)new Array\((.*)\)\);"; //@"<a href=([^>]*)>([^>]*) - ";
matchArray = [loginStatus arrayOfCaptureComponentsMatchedByRegex:regexString];
NSMutableArray *newArray = [[NSMutableArray alloc] initWithCapacity:[matchArray count]];
//NSCharacterSet *charactersToRemove = [NSCharacterSet punctuationCharacterSet];
[matchArray enumerateObjectsUsingBlock:^(NSString *aString, NSUInteger idx, BOOL *stop)
{
NSString *newString = [NSString stringByTrimmingCharactersInSet:[NSCharacterSet punctuationCharacterSet]];//#############
[newArray insertObject:newString atIndex:idx];
NSLog(@"matchArray: %@", matchArray);
}];//******************
//NSLog(@"matchArray: %@", matchArray);
lstAirports = [[NSMutableArray alloc] initWithCapacity:[matchArray count]];
for (int i = 0; i < [matchArray count]; i++) {
airport *air=[[airport alloc]init];
//code
air.Code = [[matchArray objectAtIndex: i] objectAtIndex: 1];
NSLog(@"air.Code: %@\n",air.Code);
//name
NSString *temp=[[matchArray objectAtIndex: i] objectAtIndex: 2];
NSArray *arrParts=[temp componentsSeparatedByString:@""","];
//air.Name=arrParts[2];
air.Name=[arrParts objectAtIndex:2];
NSLog(@"air.Name: %@\n",air.Name);
//destination airports
temp=[[matchArray objectAtIndex: i] objectAtIndex: 3];
arrParts=[temp componentsSeparatedByString:@","];
air.DestinationAirports =arrParts;
NSLog(@"air.DestinationAirports: %@\n",air.DestinationAirports);
[lstAirports addObject: air];
NSLog(@"lstAirports: %@\n",lstAirports);
}
//[webData release];
}
请一些人帮助我,这对我来说至关重要
答案 0 :(得分:4)
您不需要RegExp来删除NSString中出现的字符串。
请参阅下面的示例,我可以帮助您:
NSString *str = @"fdf\"fdsfdsf\"fsdfsf/fsdfsdfsf\\fsdfsdf\\fsdffsd//fsdfsf\"fsdf/\\\"";
str = [str stringByReplacingOccurrencesOfString:@"\"" withString:@""];
str = [str stringByReplacingOccurrencesOfString:@"\\" withString:@""];
str = [str stringByReplacingOccurrencesOfString:@"/" withString:@""];
NSLog(@"%@", str);
答案 1 :(得分:0)
检查
的用法 stringByReplacingOccurrencesOfString:withString
:
in
您可以用“”字符替换它们。