使用SQL Server中的XQuery将XML转换为表数据

时间:2011-09-13 10:29:03

标签: sql xquery-sql

是否可以使用SQL Server中的XQuery从输出中实现下表?

编辑:我的要求发生了变化,请考虑我有一个存储以下xml和UserID的表

DECLARE  @XML xml
set @XML = '<Security>
             <FiscalYear Name="2012">
            <Country Id="204">
              <State Id="1">
                <City Id="10"></City>
              </State>
              <State Id="2">
                <City Id="20"></City>
                <City Id="30"></City>
              </State>
              <State Id ="3"></State>
              </Country >
            </FiscalYear>
        </Security>'

CREATE TABLE #tmp_user
(UserID INT,SecurityXML XML)

INSERT INTO #tmp_user
        ( UserID, SecurityXML )
VALUES  ( 1, 
          @XML
          )

现在我怎么能得到一个类似

的o / p

输出:

 UserID StateID       CityID
     1      1           10
     1      2           20
     1      2           30
     1      3            0

有可能实现吗?

1 个答案:

答案 0 :(得分:4)

我稍微修改了你的XML,因为它无效。将结束标记</Subsidiary>更改为</Country>

declare @XML xml
set @XML = 
'<Security>
   <FiscalYear Name="2012">
     <Country Id="204">
      <State Id="1">
        <City Id="10"></City>
      </State>
      <State Id="2">
        <City Id="20"></City>
        <City Id="30"></City>
      </State>
      <State Id ="3"></State>
    </Country>
   </FiscalYear>
 </Security>'

select S.N.value('@Id', 'int') as StateID,
       coalesce(C.N.value('@Id', 'int'), 0) as CityID
from @XML.nodes('/Security/FiscalYear/Country/State') as S(N)
  outer apply S.N.nodes('City') as C(N)

使用表而不是XML变量的版本

select T.UserID,
       S.N.value('@Id', 'int') as StateID,
       coalesce(C.N.value('@Id', 'int'), 0) as CityID
from #tmp_user as T
  cross apply T.SecurityXML.nodes('/Security/FiscalYear/Country/State') as S(N)
  outer apply S.N.nodes('City') as C(N)