Question

我有类似123-123-1234的字符串，所以我想将字符串转换为这种格式（123）123-1234所以任何想法来开发这个功能。

提前致谢。

Answer 1

我认为是这样的：

NSString *list = @"123-123-1234";
NSArray *listItems = [list componentsSeparatedByString:@"-"];
NSString *result = [NSString stringWithFormat:@"(%@) %@-%@", [listItem objectAtIndex:0], [listItem objectAtIndex:1], [listItem objectAtIndex:2]];

Answer 2

测试代码：100％工作

NSString *inputString=@"123-123-1234";


NSArray *TotalString=[inputString componentsSeparatedByString:@"-"];


NSString *outputString = [NSString stringWithFormat:@"(%@) %@-%@",[TotalString objectAtIndex:0],[TotalString objectAtIndex:1],[TotalString objectAtIndex:2]];

NSLog(@"outputString is : %@ \n\n",outputString);

<强>输出： outputString是：（123）123-1234

动态溶剂：

注意：如果你的ur字符串有更多破折号，那么使用objectAtIndex编号为0,1,2，....的所有内容都很难编码。

此外，如果它有意想不到的长度，它将崩溃

所以这是这个

的解决方案

NSString *inputString=@"123-123-1234";


NSArray *TotalString=[inputString componentsSeparatedByString:@"-"];


NSMutableString *outputString=[NSMutableString string]; 
for (NSMutableString *obj in TotalString) {


    if ([TotalString objectAtIndex:0] == obj && [outputString length]<=0) {

        outputString=[[outputString stringByAppendingFormat:@"(%@)",obj] mutableCopy];


    }
    else if ([TotalString objectAtIndex:1] == obj) {

        outputString=[[outputString stringByAppendingFormat:@"%@%@",@" ",obj] mutableCopy];


    }
    else {
        outputString=[[outputString stringByAppendingFormat:@"-%@",obj] mutableCopy];

    }

}

<强>输出： outputString是：（123）123-1234

Answer 3

NSString * original = @"123-123-1234";
NSArray * components = [original componentsSeparatedByString:@"-"];
NSString * first = [NSString stringWithFormat:@"(%@)",[components objectAtIndex:0] ];
NSString * second = [NSString stringWithFormat:@"%@-%@",[components objectAtIndex:1],[components objectAtIndex:2]];
NSString * finalString = [NSString stringWithFormat:@"%@%@",first,second];
NSLog(@"Final Result = %@",finalString);

Answer 4

NSString * str = @“123-123-1234”;

NSArray * arrForDate = [str componentsSeparatedByString：@“ - ”];

NSString * str1 = [NSString stringWithFormat：@“（％@）％@ - ％@”，[arrForDate objectAtIndex：0]，[arrForDate objectAtIndex：1]，[arrForDate objectAtIndex：2]];

NSLog（@“str1％@”，str1）;

Answer 5

NSString * list = @“ 123-123-1234”; NSArray * listItems = [列出componentsSeparatedByString：@“-”]; NSString * result = [NSString stringWithFormat：@“（％@）％@-％@”，[listItem objectAtIndex：0]，[listItem objectAtIndex：1]，[listItem objectAtIndex：2]];

iPhone：将NSString 123-123-1234转换为（123）123-1234

5 个答案: