Question

这是我用于转换的代码

NSString * dateString = @"9/12/2011";
NSDateFormatter *serverDateFormatter = [[NSDateFormatter alloc] init];
[serverDateFormatter setDateFormat:@"MM/dd/yyyy"];
NSDate *serverDate = [serverDateFormatter dateFromString:dateString];
[serverDateFormatter release];

输出是 2011-09-11 19:00:00 +0000

但我只想将该nsstring转换为具有相同格式的nsdate 9/12/2011

Answer 1

试试这个。

     NSString * dateString = @"9/12/2011";
NSDateFormatter *serverDateFormatter = [[NSDateFormatter alloc] init];
[serverDateFormatter setDateFormat:@"dd/MM/yyyy"];
NSDate *serverDate = [serverDateFormatter dateFromString:dateString];
NSLog(@"%@",serverDate);

NSDateFormatter *tempDate=[[NSDateFormatter alloc]init];
[tempDate setDateFormat:@"MM/dd/yyyy"];
   NSDate *date=(NSDate *)[tempDate stringFromDate:serverDate];
NSLog(@"%@",date);

[tempDate release];
[serverDateFormatter release];

希望这会对你有帮助..

Answer 2

将此属性设置为NSDateFormatter：

[serverDateFormatter setDateStyle:NSDateFormatterShortStyle];
[serverDateFormatter setTimeStyle:NSDateFormatterNoStyle];

Answer 3

您可以尝试以下代码，因为我成功运行了该代码。

NSString * dateString = @"9/12/2011";
NSDateFormatter *serverDateFormatter = [[NSDateFormatter alloc] init];
[serverDateFormatter setDateFormat:@"d/MM/yyyy"];
NSDate *serverDate = [serverDateFormatter dateFromString:dateString];
NSLog(@"%@",serverDate);

NSDateFormatter *dateFormat = [[NSDateFormatter alloc] init];
[dateFormat setDateFormat:@"d/MM/yyyy"];
NSDate *st = (NSDate *)[dateFormat stringFromDate:serverDate];
NSLog(@"%@",st);

它的回归9/12/2011所以试试吧。

NSDateFormatter未正确将NSString转换为NSdate

3 个答案: