CFArrayGetValueAtIndex返回非ABRecordRef

时间:2011-09-12 00:30:46

标签: iphone objective-c cocoa-touch ios4

我在某些用户的iPhone上遇到了崩溃,我终于找到了一个可以复制问题的人。这是代码的关键部分

ABAddressBookRef addressbook = ABAddressBookCreate();
if( addressbook )
{
    //Got this via http://stackoverflow.com/questions/4641229/code-example-for-abaddressbookcopyarrayofallpeopleinsourcewithsortordering
    ABRecordRef source = ABAddressBookCopyDefaultSource(addressbook);
    CFArrayRef sortedPeople = ABAddressBookCopyArrayOfAllPeopleInSourceWithSortOrdering(addressbook, source, kABPersonSortByFirstName);
    //Sort them first

    if( sortedPeople )
    {
        CFIndex contactCount = ABAddressBookGetPersonCount(addressbook);

        for( int i = 0; i<contactCount; i++ )
        {
            ABRecordRef ref = CFArrayGetValueAtIndex(sortedPeople, i);
            NSMutableString *fName = [[[NSMutableString alloc] init] autorelease];
            NSMutableString *lName = [[[NSMutableString alloc] init] autorelease];
            NSMutableDictionary *identifiers = [[[NSMutableDictionary alloc]init]autorelease];
            if( ref )
            {
                //Get the user's name first
                NSLog(@"%@ is the reference", ref);
                CFStringRef firstName = ABRecordCopyValue(ref, kABPersonFirstNameProperty);
                if( firstName )
                {
                    NSString *fn = [NSString stringWithFormat:@"%@",firstName];
                    if([fn hasPrefix:@"(null"])
                        [fName appendString:@""];
                    else
                    {
                        [fName appendString:[NSString stringWithFormat:@"%@", firstName]];
                        [fName setString:[fName stringByReplacingCharactersInRange:NSMakeRange(0,1) withString:[[fName substringToIndex:1]uppercaseString]]];
                    }
                    CFRelease(firstName);
                }
           }
       }
   }
}

显然是这行代码的结果:     ABRecordRef ref = CFArrayGetValueAtIndex(sortedPeople,i);

有时会以NSCFType而不是ABPerson的形式返回。有关如何检查结果类型的任何想法?我试图阻止这种情况导致用户手机崩溃。一旦我到达这一行:

 ABRecordCopyValue(ref, kABPersonFirstNameProperty);

我在这一行得到了一个EXC_BAD_ACCESS。当日志文件如下所示时会发生这种情况:

2011-09-11 17:24:31.355 Holler[1345:707] <CPRecord: 0x6642fb0 ABPerson> is the reference
2011-09-11 17:24:31.358 Holler[1345:707] <CPRecord: 0x66431d0 ABPerson> is the reference
2011-09-11 17:24:31.361 Holler[1345:707] <CPRecord: 0x66433b0 ABPerson> is the reference
2011-09-11 17:24:31.365 Holler[1345:707] <CPRecord: 0x6640fd0 ABPerson> is the reference
2011-09-11 17:24:31.369 Holler[1345:707] <CPRecord: 0x6643510 ABPerson> is the reference
2011-09-11 17:24:31.372 Holler[1345:707] __NSCFType is the reference

任何帮助都将非常感谢!!!

2 个答案:

答案 0 :(得分:7)

我很确定发生崩溃是因为contactCount设置错误:

  • sortedPeople设置为一个来源的所有人
  • contactCount设置为地址簿中所有人的计数

因此,如果您的地址簿中有多个包含人员的来源,则迭代将离开sortedPeople的边界。要解决此问题,请替换

CFIndex contactCount = ABAddressBookGetPersonCount(addressbook);

CFIndex contactCount = CFArrayGetCount(sortedPeople);

答案 1 :(得分:0)

您可以使用ABRecordGetRecordType(ref) == kABPersonType键入 - 检查地址簿结果,以确保它是ABPerson,而不是ABGroup