Question

这是$ distribution数组

Array
(
    [ASCM72X36] => Array
        (
            [item_code] => ASCM72X36
            [quantity] => 5
            [selling_price] => 6758.00
        )

    [ASCM72X48] => Array
        (
            [item_code] => ASCM72X48
            [quantity] => 5
            [selling_price] => 
        )

    [ASCM72X60] => Array
        (
            [item_code] => ASCM72X60
            [quantity] => 5
            [selling_price] => 8544.00
        )
)

这是$ sold数组

    Array
    (
        [ASCM72X36] => Array
            (
                [item_code] => ASCM72X36
                [quantity] => 1.0
            )

        [ASCM72X60] => Array
            (
                [item_code] => ASCM72X60
                [quantity] => 1.0
            )
)

所以即时比较键并使用新数量构建新的$ responce数组并过滤出数量为0的产品，如下所示

    $i=0;
    foreach($distribution as $key => $new_distribution)
    {
      $newqty = $new_distribution['quantity'] - $sold[$key]['quantity'];
      if( $newqty != 0 && $new_distribution['selling_price'] != ""){
        $responce->data[$i]['item_code'] = $new_distribution['item_code'];
        $responce->data[$i]['quantity'] = $newqty;
        $responce->data[$i]['selling_price'] = $new_distribution['selling_price'];
      }
    $i++;

}

然后我需要让json编码输出所以即时通讯这样做

echo json_encode($responce);

即时退出

{"data":{"0":{"item_code":"ASCM72X36","quantity":4,"selling_price":"6758.00"},"2":{"item_code":"ASCM72X60","quantity":4,"selling_price":"8544.00"}}}

问题是在json中得到“0”，“2”等。如何在不使用“0”和“2”之类的情况下防止这种情况并获得出局......？

{"data":{"item_code":"ASCM72X36","quantity":4,"selling_price":"6758.00"},{"item_code":"ASCM72X60","quantity":4,"selling_price":"8544.00"}}

Answer 1

似乎你正在编码对象。你想要的方式必须编码数据变量

 echo json_encode(array("data"=>$responce->data));

如果编码一个以字符串作为索引的数组，则该数组将成为json编码字符串中的一个对象。

Plase，试试这个：

foreach($distribution as $key => $new_distribution)
{
  $newqty = $new_distribution['quantity'] - $sold[$key]['quantity'];
  if( $newqty != 0 && $new_distribution['selling_price'] != ""){
    $arr=array();
    $arr['item_code'] = $new_distribution['item_code'];
    $arr['quantity'] = $newqty;
    $arr['selling_price'] = $new_distribution['selling_price'];
    $responce->data[] = $arr;
  }

}

Answer 2

您正在获取索引，因为您正在跳过值。即，您的数组是关联的，而不是数字。

尝试运行

$responce->data = array_values($responce->data)

最后重新编制索引。更好的是，将[$i]放在作业中，然后执行

$responce->data[] = ....

另外，你拼错了“回复”。

如果这些都不起作用，如果您运行的是PHP 5.3.3或更高版本，请查看JSON_NUMERIC_CHECK。 http://ca2.php.net/manual/en/function.json-encode.php

在这种情况下如何获得正确的json输出？

2 个答案: