如何在iPhone中使用自定义数字键盘显示单点？

Question

我正在创建自定义NumberPad

if (([[[UIDevice currentDevice] systemVersion] doubleValue] >= 4.1)) {
    inputBoxTextField.keyboardType = UIKeyboardTypeDecimalPad;
}

我的问题是，我想只显示一次点。

提前感谢。

Answer 1

如果您想允许用户只输入一个点，您可以使用委托方法

-(BOOL) textField:(UITextField *)textField shouldChangeCharactersInRange:(NSRange)range replacementString:(NSString *)string

只需检查textField是否已包含点。

Answer 2

- (BOOL)textField:(UITextField *)textField shouldChangeCharactersInRange:(NSRange)range replacementString:(NSString *)string {

NSNumberFormatter *numberFormatter = [[NSNumberFormatter alloc] init];
[numberFormatter setNumberStyle:NSNumberFormatterDecimalStyle];

NSNumber* candidateNumber;

NSString* candidateString = [textField.text stringByReplacingCharactersInRange:range withString:string];

range = NSMakeRange(0, [candidateString length]);

[numberFormatter getObjectValue:&candidateNumber forString:candidateString range:&range error:nil];

if (([candidateString length] > 0) && (candidateNumber == nil || range.length < [candidateString length])) {

    return NO;
}
else {
    return YES; } }

Answer 3

我使用以下代码。适合我，并且代码更少。

- (BOOL)textField:(UITextField *)textField shouldChangeCharactersInRange:(NSRange)range replacementString:(NSString *)string {

    NSNumberFormatter *numberFormatter = [[NSNumberFormatter alloc] init];
    [numberFormatter setNumberStyle:NSNumberFormatterDecimalStyle];
    NSString *decimalSymbol = [numberFormatter decimalSeparator];

    if(([textField.text rangeOfString:decimalSymbol].location != NSNotFound) &&
       ([string rangeOfString:decimalSymbol].location != NSNotFound)) {
        return NO;
    }
return YES; 
}