Question

我有一个EAV表（每行中都有简单的键/值），我需要从两行中取出'value'并将它们连接成一行，只有一列。我似乎无法通过直接转向的部分。任何人都可以帮我解决这个问题吗？

Declare @eavHelp Table
(
    [Key]         VARCHAR (8)       NOT NULL,
    [Value]       VARCHAR (8)      NULL
)
Insert Into @eavHelp Values ( 'key1' , 'aaa' )    
Insert Into @eavHelp Values ( 'key2' , 'bbb' )

Select * From @eavHelp 
Pivot
(   Min( [Value] ) 
    For [Value] in ( hmm1 , hmm2 )
)
as Piv Where [Key] = 'key1' or [Key] = 'key2'

这样做：

Key      hmm1     hmm2
-------- -------- --------
key1     NULL     NULL
key2     NULL     NULL

但我想做的是：

hmmmX
-----
aaa;bbb

Answer 1

不需要转动。

编辑添加新要求（;分隔符）：

SELECT hmmmX = STUFF((SELECT ';' + [Value] FROM @eavHelp 
    WHERE [Key] IN ('key1', 'key2')
    FOR XML PATH(''), TYPE).value('.', 'VARCHAR(MAX)'), 1, 1, '');

Answer 2

Declare @eavHelp Table 
( 
    [Key]         VARCHAR (8)       NOT NULL, 
    [Value]       VARCHAR (8)      NULL 
) 
Insert Into @eavHelp Values ( 'key1' , 'aaa' )     
Insert Into @eavHelp Values ( 'key2' , 'bbb' ) 

declare @concat nvarchar(max); select @concat =''
select @concat =@concat+case when len(@concat)>0 then '; ' else '' end + value from    @eavHelp
select @concat

透视获取EAV数据

2 个答案: