Question

我有以下表格：

Actual         Optional
------         --------
4                 3
13                6
20                7
26                14
                  19
                  21
                  27
                  28

我要做的就是选择：

1）“实际”表中的所有值。

2）如果它们形成连续，则从“可选”表中选择值   具有“实际”表值的系列

预期结果是：

Answer
------
4
13
20
26
3    --because it is consecutive to 4 (i.e 3=4-1) 
14   --14=13+1
19   --19=20-1
21   --21=20+1
27   --27=26+1
28   --this is the important case.28 is not consecutive to 26 but 27 
     --is consecutive to 26 and 26,27,28 together form a series.

我使用递归cte编写了一个查询但是它永远循环并且在递归达到100级后失败。我遇到的问题是27场比赛26场比赛，28场比赛27场比赛27场比赛27场比赛28场比赛27场比赛......（永远）

这是我写的查询：

with recurcte as
        (
        select num as one,num as two from actual
        union all
         select opt.num as one,cte.two as two 
         from recurcte cte join optional opt 
         on opt.num+1=cte.one or opt.num-1=cte.one
        )select * from recurcte

Answer 1

;WITH Combined
     AS (SELECT 1 AS Actual, N
         FROM   (VALUES(4),
                       (13),
                       (20),
                       (26)) Actual(N)
         UNION ALL
         SELECT 0 AS Actual, N
         FROM   (VALUES(3),
                       (6),
                       (7),
                       (14),
                       (19),
                       (21),
                       (27),
                       (28)) Optional (N)),
     T1
     AS (SELECT *,
                N - DENSE_RANK() OVER (ORDER BY N) AS Grp
         FROM   Combined),
     T2
     AS (SELECT *,
                MAX(Actual) OVER (PARTITION BY Grp) AS HasActual
         FROM   T1)
SELECT DISTINCT N
FROM   T2
WHERE  HasActual = 1

Answer 2

此CTE将为您提供您正在寻找的数据。这不需要递归。

declare @Actual table (i int)
declare @Optional table (i int)

insert into @Actual 
    select 4 union select 13 union select 20 union select 26

insert into @Optional 
    select 3 union select 6 union select 7 union select 14 union select 19
    union select 21 union select 27 union select 28

;with rownum as (
    select *, ROW_NUMBER() OVER (ORDER BY i) as 'RN'
    from (
        select
            i, 'A' as 'Source'
        from
            @Actual
        union
        select
            i, 'O'
        from
            @Optional
    ) a
)

select distinct
    d.i
from
    rownum a
    inner join rownum d
        on  a.i - d.i = a.rn - d.rn
where
    a.source = 'A'

使用递归公用表表达式从两个表中查找连续的no.s

2 个答案: