Question

我有带有android：numeric =“decimal”的EditText字段和用于输入十进制数字的android：inputType =“phone”。我使用输入型手机，因为用户输入数字更容易。

对于任何带有软键盘的设备，我没有任何问题，但是当我开始使用硬键盘时会打印错误的数字（例如当我使用HTC Desire Z时）。

如何解决这个问题？

P.S。我为Android开发了“Simple Loan Calculator” - 它是开源和免费软件

Answer 1

解决！

<强>的AndroidManifest.xml

<activity android:name=".MainActivity" android:label="@string/app_name" android:configChanges="keyboardHidden|orientation|keyboard" >

<强> MainActivity.java

public void onCreate(Bundle savedInstanceState) {
    ....
    setPriceInputFilter(amountEdit, interestEdit, fixedPaymentEdit, periodYearEdit, periodMonthEdit, downPaymentEdit, disposableCommissionEdit, monthlyCommissionEdit);
    ....
}
private void setPriceInputFilter(EditText ... fields){
  PriceInputFilter filter = new PriceInputFilter();
  for (EditText field: fields){
    field.setFilters(new InputFilter[]{filter});
  }
}
public void onConfigurationChanged(Configuration newConfig) {
    if(newConfig.hardKeyboardHidden == Configuration.HARDKEYBOARDHIDDEN_NO){
       setInputType(InputType.TYPE_NULL, amountEdit, interestEdit, fixedPaymentEdit, periodYearEdit, 
                                         periodMonthEdit, downPaymentEdit, disposableCommissionEdit, monthlyCommissionEdit);
       Toast.makeText(this, "HARD-keyboard", Toast.LENGTH_SHORT).show();
    }else{
      setInputType(InputType.TYPE_CLASS_PHONE, amountEdit, interestEdit, fixedPaymentEdit, periodYearEdit, 
                                               periodMonthEdit, downPaymentEdit, disposableCommissionEdit, monthlyCommissionEdit);
      Toast.makeText(this, "SOFT-keyboard", Toast.LENGTH_SHORT).show();
    }
    super.onConfigurationChanged(newConfig);
}
private void setInputType(int type , EditText ... fields){
    for (EditText field: fields){
      field.setInputType(type);
    }
}

<强> PriceInputFilter.java

public class PriceInputFilter implements InputFilter {
  public CharSequence filter(CharSequence source, int start, int end,  Spanned dest, int dstart, int dend) {
    String checkedText = dest.toString() + source.toString();
    String pattern = getPattern();
    if (!Pattern.matches(pattern, checkedText)) {
      return "";
    }
    return null;
  }
  private String getPattern() {
    return "[0-9]+([.]{1}||[.]{1}[0-9]{1,2})?";
  }
}

使用硬键盘时EditText中的输入数字错误

1 个答案: