Question

我想在一个将发布到自身的页面中实现Post / Redirect / Get模式。

表单是我正在构建的MVC应用程序的一部分，表单字段是在php中生成的。

表单位于此处：http://site.com/mycontroller/myaction/

以下是“myaction”的相关代码（请注意，会话已经启动，所以我可以从$ _SESSION读取和写入）：

public function myaction(){



 $login = $_POST['comment'];

    if(isset($comment)){
       //I am not doing any real checking here as I am just testing the redirect. Just checking to see if a value was supplied to the comment text input.
       $_SESSION['test'] = 'SUCCESS';

       //Insert the comment here (into some database).

       header("Location: http://site.com/mycontroller/myaction/", 302);
       exit();

       echo "<BR>Thanks for commenting! <BR>";
    }else{
       //Show the form here.
       //The form posts to itself, so the action looks like: <form action="" method="POST">
    }
}

上述代码工作正常，如果用户刷新或使用后退按钮，则不会要求他通过浏览器重新发布数据。

问题是我想在插入评论时显示“感谢评论”的消息。同时，如果他们提供了空白评论，我想显示表格和“请输入评论！”的消息。

我如何实施这两项要求？

干杯：）

Answer 1

有3种可能的解决方案

忘记PRG并选择AJAX
as heximal说
将您的消息写入会话

对于错误消息，您可以将其显示在原位，而无需重定向。它的缺点是，如果用户最终未能填写表单，则要求用户重新加载页面，但通常认为这可以忽略不计。

Answer 2

我会做以下事情：

header("Location: http://site.com/mycontroller/myaction/?aftercomment=true", 302);

在myaction脚本中

：

if ($_GET['aftercomment']) echo('Thanks for comment!');

Answer 3

public function myaction(){

 if(isset($_GET['ok'])) {
    echo "<BR>Thanks for commenting! <BR>";
 }

 $comment = $_POST['comment'];

    if(isset($comment)){
       //I am not doing any real checking here as I am just testing the redirect. Just checking to see if a value was supplied to the comment text input.
       $_SESSION['test'] = 'SUCCESS';

       //Insert the comment here (into some database).

       header("Location: http://site.com/mycontroller/myaction/?ok=1", 302);
       exit();

       echo "<BR>Thanks for commenting! <BR>";
    }else{
       echo  "Please enter a comment!";
       //Show the form here.
       //The form posts to itself, so the action looks like: <form action="" method="POST">
    }
}

发布/重定向/获取表单发布到自身

3 个答案: