从两个表中获取数据?

时间:2011-09-09 03:36:44

标签: sql oracle oracle10g sqlplus

我正在尝试从两个不同的表中获取数据并将其放入on语句但它无效。这是我希望得到的完整声明:我希望查询显示dname,loc,人数。我遇到了子查询的问题。

 SQL> select dname, loc from dept where ename in (count(ename) AS Number_of_People  from emp);
select dname, loc from dept where ename in (count(ename) AS Number_of_People from emp)
                                        *
ERROR at line 1:
 ORA-00934: group function is not allowed here


SQL>

表emp

SQL> select empno, ename, job, hiredate, deptno from emp;

 EMPNO ENAME      JOB       HIREDATE      DEPTNO
 ---------- ---------- --------- --------- ----------
  7839 KING       PRESIDENT 17-NOV-81         10
  7698 BLAKE      MANAGER   01-MAY-81         30
  7782 CLARK      MANAGER   09-JUN-81         10
  7566 JONES      MANAGER   02-APR-81         20
  7654 MARTIN     SALESMAN  28-SEP-81         30
  7499 ALLEN      SALESMAN  20-FEB-81         30
  7844 TURNER     SALESMAN  08-SEP-81         30
  7900 JAMES      CLERK     03-DEC-81         30
  7521 WARD       SALESMAN  22-FEB-81         30
  7902 FORD       ANALYST   03-DEC-81         20
  7369 SMITH      CLERK     17-DEC-80         20

 EMPNO ENAME      JOB       HIREDATE      DEPTNO
 ---------- ---------- --------- --------- ----------
  7788 SCOTT      ANALYST   09-DEC-82         20
  7876 ADAMS      CLERK     12-JAN-83         20
  7934 MILLER     CLERK     23-JAN-82         10

 14 rows selected.

 SQL>

表部门

 SQL> select * from dept;

 DEPTNO DNAME          LOC
  ---------- -------------- -------------
    10 ACCOUNTING     NEW YORK
    20 RESEARCH       DALLAS
    30 SALES          CHICAGO
    40 OPERATIONS     BOSTON

   SQL>  

3 个答案:

答案 0 :(得分:0)

我不确定你要做什么,但突出的是你可能需要在你的子查询中使用select。尝试:

select dname, loc 
from dept 
where ename in (select count(ename) AS Number_of_People  from emp);

答案 1 :(得分:0)

你想要达到这样的目标吗?

select dname, loc, (select count(ename) from emp where DEPTNO = dept.deptno) as Number_of_people 
from dept;

答案 2 :(得分:0)

试试这个

select dept.dname, dept.loc,count(*) 
from emp 
join dept on emp.deptNo=dept.deptno
group by dept.dname,dept.loc