Question

我正在使用谷歌地图地理编码地址以便在地图上显示。我循环遍历每个地址并通过jquery回调处理响应。

如何识别回电来自哪个项目？

var geocoder = new google.maps.Geocoder();
geocoder.geocode({ 'address': addr }, function (results, status) {
    if (status == google.maps.GeocoderStatus.OK) {
        var marker = new google.maps.Marker({ position: results[0].geometry.location, map: map, title: "Yo Homie" });
        // I need to find the item to setup the infowindow
        bounds.extend(results[0].geometry.location);
        map.fitBounds(bounds);
    }
    else {
        // eat it like a mexican jumping bean
    }
});

Answer 1

我将地理编码器调用包装到一个函数中，将您的对象传递给该函数，然后您也可以在地理编码器的回调中使用它。

示例：

// i'm just staging a fake for loop here... 
for(var i = 0; i < 10; i++){

    // this is your basic object
    var obj = {address: "Brussels Belgium"};
    // here you call the geo function and pass the object so that you can access it inside the function
    doGeoCode(obj);
}

function doGeoCode(obj) {
  // your geocoder wrapped in a function, takes 1 argument which you can reference in the callback below
  var geocoder;
  geocoder = new google.maps.Geocoder();
  geocoder.geocode( { 'address': obj.address}, function(results, status) {
    if (status == google.maps.GeocoderStatus.OK) {
      var p = results[0].geometry.location;

      // inside this callback function you can just reference 'obj' 
      obj.position = {'longitude': p.lng(), 'latitude': p.lat()};
    } else {
      // your mexican thingy
    }
  });
}

Answer 2

请您提供更多代码？查看当前代码，我假设您发布的所有代码都在循环内，而addr是您列表的单个地址。如果是这样，那么您应该可以在回调函数（结果，状态）中访问addr。

从回调中识别对象

2 个答案: