Question

我似乎无法将从目录扫描填充的链接适当地添加到LINK。当我单击填充的链接时，它当前引用当前目录而不是孙子目录dir_2 / dir_3。任何帮助都将非常感激。

 <?php

  // These files will be ignored
  $excludedFiles = array (
'excludeMe.file',
'excludeMeAs.well'
);

// These file extensions will be ignored
$excludedExtensions = array (
  'html',
'xslt',
'htm',
'ahk',
'xsl',
'txt',
'xml'
);

// Make sure we ignore . and ..
$excludedFiles = array_merge($excludedFiles,array('.','..')); 

 // Convert to lower case so we are not case-sensitive
 for ($i = 0; isset($excludedFiles[$i]); $i++) $excludedFiles[$i] =        
 strtolower(ltrim($excludedFiles[$i],'.'));
  for ($i = 0; isset($excludedExtensions[$i]); $i++) $excludedExtensions[$i] =    
 strtolower($excludedExtensions[$i]);

  // Loop through directory
  $count = 0;
  if ($handle = opendir('dir_2/dir_3')) {
  while (false !== ($file = readdir($handle))) {
  $extn = explode('.',$file);
  $extn = array_pop($extn);
  // Only echo links for files that don't match our rules
  if (!in_array(strtolower($file),$excludedFiles) &&   
  !in_array(strtolower($extn),$excludedExtensions)) {
    $count++;
    print("<a href=\"".$file."\">".$file."</a><br />\n");
  }
}
echo '<br /><br /><a href="..">Return</a>';
closedir($handle);
}

?>

Answer 1

您需要将您正在查看的目录附加到链接。

$dir = 'dir_2/dir_3';
if ($handle = opendir($dir)) {
// snip
print("<a href=\"".$dir.$file."\">".$file."</a><br />\n");

如何将来自孙子目录的文件从当前dir与PHP opendir的两个级别链接起来？

1 个答案: