Question

我使用此代码：

from __future__ import division
from __future__ import print_function

in_file = open("s:/Personal Folders/Andy/Python Projects/People Cancelled/Analyze Authorize Truncated.csv")
text = in_file.readlines()
in_file.close()

header = text[0:1]
text = text[1:]

for index, line in enumerate(text):
    text[index] = line.split(",")

name = text
dates = text

for index, line in enumerate(name):
    name[index] = line[3:5]

for stuff, area in enumerate(dates):
     dates[stuff] = area[7:8]

print(name)
print(dates)

我得到了这个输出：

 [[], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], []]
 [[], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], []]

知道为什么吗？出于某种原因，两个for循环之间似乎存在某种干扰 - 如果我单独进行，我会得到我想要的结果。

谢谢！

Answer 1

看看这两行：

name = text
date = text

这些行不制作名称和日期的文本副本以指向;相反，他们将名称和日期设置为文本的替代名称。因此，在第三个for循环之后（使用正文name[index] = line[3:5]，text中的每一行都是两个项目（因为text和name是相同的列表）。事实上，我甚至不知道为什么你最初将name和date都设置为text;只需制作name和date就可以达到预期效果等于新的空列表，并根据text向它们追加项目。

获取空白列表 - 不知道为什么？

1 个答案: