Question

问题描述：抬起一堆硬币。翻转最顶部的硬币，然后继续：将前2个硬币和上翻作为单个堆叠（尾部，头部朝上翻转并放回堆叠尾部，头部（两个硬币翻转就好像粘在一起））。现在以相同的方式翻转前3个硬币并放回堆叠（你得到：尾巴，尾巴，头部（如果有4个硬币，那将是尾巴，尾巴，尾巴，头部）。当你翻转整个堆叠用第一枚硬币再次开始。继续，直到你回到所有抬头的堆叠。

（希望明白）

有人能看出为什么这个小程序会失败吗？对我来说，我第一次注意到错误的例子是当计数达到18时，堆叠了6个硬币。

我在电子表格上放了一个按钮，然后调用FlippingCoins ......

Sub FlippingCoins()
Call theStackOfCoins
Call theFlipping
End Sub


Sub theStackOfCoins()
Worksheets("Sheet3").Cells(1, 3).Select
Columns("A:b").Select
Selection.ClearContents
Range("a3").Select

Dim StackOfCoins As Integer
    StackOfCoins = Worksheets("Sheet3").Cells(1, 3).Value

Dim row As Integer
    row = 0

For theStack = 1 To StackOfCoins
    Worksheets("Sheet3").Cells(row + theStack, 1).Value = True
Next theStack

End Sub

Sub theFlipping()

Dim middleCoin As Integer
    middleCoin = 0
Dim passes As Integer
    passes = 0
Dim Fst As Integer
    Fst = 0
Dim Lst As Integer
    Lst = 0

Dim stack As Integer
    stack = Worksheets("Sheet3").Cells(1, 3).Value

Dim Flip_x_coins As Integer
    Flip_x_coins = 0

Dim count As Integer
    count = 0

Dim Finished As Boolean
    Finished = False

Reset:
    Flip_x_coins = 1
For Flip_x_coins = 1 To stack
    Worksheets("Sheet3").Cells(1, 4).Value = Flip_x_coins
    count = count + 1
    If Flip_x_coins = 1 Then
        Worksheets("Sheet3").Cells(1, 1).Value = Not (Worksheets("Sheet3").Cells(1, 1).Value)
    Else
        passes = Int(Flip_x_coins) / 2
        Fst = 1
        Lst = Flip_x_coins
        For pass = 1 To passes
            If Worksheets("Sheet3").Cells(Fst, 1).Value = Worksheets("Sheet3").Cells(Lst, 1).Value Then
                    Worksheets("Sheet3").Cells(Fst, 1).Value = Not (Worksheets("Sheet3").Cells(Fst, 1).Value)
                    Worksheets("Sheet3").Cells(Lst, 1).Value = Not (Worksheets("Sheet3").Cells(Lst, 1).Value)
            End If
            Fst = Fst + 1
            Lst = Flip_x_coins - 1
        Next pass
        If Flip_x_coins Mod 2 > 0 Then
            middleCoin = (Flip_x_coins + 1) / 2
            Worksheets("Sheet3").Cells(middleCoin, 1).Value = Not (Worksheets("Sheet3").Cells(middleCoin, 1).Value)
        End If
    End If
    For testComplete = 1 To stack
        If Worksheets("Sheet3").Cells(testComplete, 1).Value = False Then
            Finished = False
            Exit For
        Else
            Finished = True
        End If
    Next testComplete
    Worksheets("Sheet3").Cells(1, 2).Value = count
If Finished = True Then
    Exit For
End If
    MsgBox "Next."
    If Flip_x_coins = stack Then
        GoTo Reset
    End If
Next Flip_x_coins

End Sub

提前致谢

此致

Answer 1

在For pass = 1 To passes循环中，Lst = Flip_x_coins - 1错误。

应该是：Lst = Lst - 1

在第18行中有6个硬币，宏比较第1行和第6行，然后是第2行和第5行，然后是第3行和第5行。显然，最后一次比较应该在第3行和第4行之间。

我希望这不是作业，因为宏还有很多其他问题。例如：

没有Option Explicit。这允许您使用三个尚未声明的变量 - theStack，pass，testComplete
不正确的舍入。鉴于Flip_x_coins属于Integer类型，passes = Int(Flip_x_coins) / 2是无意义的。请尝试使用passes = Int(Flip_x_coins / 2)
使用Goto通常是一个坏主意。它在VBA中用于错误处理，但在这种情况下，您可以轻松地使用Do Until finished ... Loop构造

Answer 2

Sub Flip()

    Dim rw As Range
    Dim numCoins As Integer
    Dim iCoins As Integer, iCoin As Integer, flipCoins As Integer
    Dim v
    numCoins = 6

    Set rw = Sheet1.Range("B2").Resize(1, numCoins) 'all start as "TRUE"
    rw.Value = True

    Do
        For flipCoins = 1 To numCoins
            For iCoin = 1 To numCoins
                If iCoin <= flipCoins Then
                    v = Not rw.Cells(flipCoins - (iCoin - 1)).Value
                Else
                    v = rw.Cells(iCoin).Value
                End If
                rw.Offset(1, 0).Cells(iCoin).Value = v
            Next iCoin
            Set rw = rw.Offset(1, 0)
            rw.EntireRow.Cells(1).Value = "Flipped " & flipCoins

            If Application.CountIf(rw, "FALSE") = 0 Then
                Debug.Print "All Heads at row " & rw.Row
                Exit Do
            End If
       Next flipCoins
   Loop While rw.Row < 1000 'don't go on for ever...
End Sub

Answer 3

我怀疑这个

            Fst = Fst + 1
            Lst = Flip_x_coins - 1
        Next pass

应该是

            Fst = Fst + 1
            Lst = Lst - 1
        Next pass

我似乎无法发现一个错误，错误的逻辑？

3 个答案: