我有一个NSDate
对象有价值,例如:“2011-08-26 14:14:51”,我想显示“2011年8月8日”如何实现它?谢谢。
答案 0 :(得分:16)
NSDate *date = [NSDate date]; //I'm using this just to show the this is how you convert a date
NSDateFormatter *df = [[NSDateFormatter alloc] init];
[df setDateStyle:NSDateFormatterLongStyle]; // day, Full month and year
[df setTimeStyle:NSDateFormatterNoStyle]; // nothing
NSString *dateString = [df stringFromDate:date]; [df release];
答案 1 :(得分:12)
NSDateFormatter *df = [[[NSDateFormatter alloc] init] autorelease];
[df setDateFormat:@"dd LLLL yyyy"];
NSString *formattedDate = [df stringFromDate:[NSDate date]];
答案 2 :(得分:6)
NSString *dateStr = @"2011-08-26 14:14:51";
//if you have date then,
NSString *dateStr = [NSString stringWithFormat:@"%@",yourDate];
NSDateFormatter *dateFormat = [[NSDateFormatter alloc] init];
[dateFormat setDateFormat:@"YYYY-MM-dd HH:mm:ss"];
NSDate *date = [dateFormat dateFromString:dateStr];
[dateFormat setDateFormat:@"MMMM dd, YYYY"];
NSString* temp = [dateFormat stringFromDate:date];
[dateFormat release];
NSLog(@"%@",temp);