Question

我想以下列格式显示数字

，格式为“123-456-7890”

我正在使用

NSNumberFormatter *formatter = [[NSNumberFormatter alloc] init];
[formatter setNumberStyle:NSNumberFormatterNoStyle];
[formatter setPositiveFormat:@"###-###-####"];
[formatter setLenient:YES];

amountField.text =[formatter stringFromNumber:[NSNumber numberWithDouble:[rxAlertResponse.rxPhoneNo doubleValue]]];
NSLog(@"%@",amountField.text);

我使用上面的代码来做到这一点，但是代码没有反映.....而且输出显示为1234567890只有任何身体可以帮助如何做到这一点。

Answer 1

使用此格式化程序：

NSNumberFormatter *formatter = [[NSNumberFormatter alloc] init]; 
    //[formatter setNumberStyle:NSNumberFormatterNoStyle];
    //[formatter setPositiveFormat:@"###-###-####"]; 
    [formatter setGroupingSeparator:@"-"];
    [formatter setGroupingSize:4];
    [formatter setUsesGroupingSeparator:YES];
       [formatter setSecondaryGroupingSize:3];
    //[formatter setLenient:YES];
    NSString *num = @"1234567890";
    NSString *str = [formatter stringFromNumber:[NSNumber numberWithInt:[num intValue]]];
    NSLog(@"%@",str);

Answer 2

在该代码中检查

tempStr = [NSString stringWithFormat:@"1(%@)%@-%@", areaCode, phone1, phone2];

作为

tempStr = [NSString stringWithFormat:@"%@-%@-%@", areaCode, phone1, phone2]

PhoneNumberFormatter.m中的

Answer 3

setPositiveFormat将' - '分隔符视为减号。

注意：请参阅Number Format Patterns

解决方法是指定'，'分隔符并替换它们：

NSNumber *phoneNumber = [NSNumber numberWithDouble:[rxAlertResponse.rxPhoneNo doubleValue]];
NSString *text =[formatter stringFromNumber:phoneNumber];
amountField.text = [text stringByReplacingOccurrencesOfString:@"," withString:@"-"];

Answer 4

快捷键：

let numberFormatter = NumberFormatter()
numberFormatter.groupingSeparator = "-"
numberFormatter.groupingSize = 4
numberFormatter.usesGroupingSeparator = true
numberFormatter.secondaryGroupingSize = 3
let number = "1234567890"
let formattedNumber = numberFormatter.string(from: NSNumber(value: Int(number)!))
print(formattedNumber as Any)

特定号码格式化器到电话号码

4 个答案: