Question

我正在寻找可以使用GPS坐标的Python库。比方说，我有一个坐标列表：

>>> gps = [
...  (53.25012925, −6.24479338, 349.9, '2011-08-20T09:35:00Z'),
...  (53.25028285, -6.24441800, 359.9, '2011-08-20T09:35:30Z'),
...  (53.25049500, -6.24266032, 395.9, '2011-08-20T09:36:00Z'),
...  # and so on...
... ]
>>>

我想计算平均速度，距离，获取最高点以及其他信息。我知道，计算它很简单，但我想知道是否有任何现有的代码（我不喜欢重新发明轮子）。

注意：stackoverflow（Which gps library would you recommend for python?）中也有类似的问题，但它与GPSD有关。我没有使用任何设备，我只是在文本文件中有GPS坐标。

Answer 1

您仍然可以使用GPSD的数据部分，而不是从头开始编写内容。以下代码来自GPSD源，并有一个模块，用于从GPS数据流中制作路径（然后获取路径长度等等）

http://code.google.com/p/python-gpsd/source/browse/src/nmea/track.py

class Track(object):

    def __init__(self, recordDelay=10, maxSize=3600, ignoreDuplicates=True, duplicateRange=0.0001):
        """ Constructor

        The default values allow for 10 hours worth of data recorded
        at 10 second intervals.

        recordDelay - Delay between recording data points
        maxSize - Maximum number of points to record
        ignoreDuplicates - Ignore entries that are very similar (ie moved a minimal distance)
        duplicateRange - Varience range within a duplicate is detected (adjust to account for
            subtle gps position drift)
        """
        self.recordDelay = recordDelay
        self.maxSize = maxSize
        self.ignoreDuplicates = ignoreDuplicates
        self.duplicateRange = duplicateRange
        self.positions = []
        self.latest = None

    def append(self, position, heading, timeStamp=None):
        """ Append position and heading information """
        if timeStamp is None: timeStamp = datetime.utcnow()

        self.latest = (timeStamp, position, heading)
        if len(self.positions):
            last = self.positions[0]
        else:
            last = None

        # Make sure we re in range
        if last is None or (timeStamp - last[0]).seconds >= self.recordDelay:
            self.positions.insert(0, self.latest)
            self.latest = None

        # Clear extra data
        if len(self.positions) > self.maxSize: pass

    def clear(self):
        """ Clear all items from track """
        self.positions = []
        self.latest = None

    def __len__(self):
        """ Return the length of the track """
        if self.latest is None: return len(self.positions)
        return len(self.positions) + 1

    def __getslice__(self, i, j):
        return self.positions[i:j]

    def __getitem__(self, i):
        return self.positions[i]

    def get_latest(self):
        if self.latest is None and len(self.positions) > 0:
            return self.positions

    def get_by_time(self, timeRange, now=datetime.utcnow()):
        """ Returns the last n items within the time range """
        result = []
        if self.latest is not None: result.append(self.latest)
        for position in self.positions:
            if (now - position[0]).seconds > timeRange: break
            result.append(position)
        return result

Answer 2

我找到了一个名为geopy的有趣库。它可以计算两个GPS点之间的距离（它使用大圆距离和Vincenty距离方法）。最重要的是， geopy 可以进行地理编码（它可以从地址获取GPS坐标）。

其他功能（平均速度，最高点等）我可以自己破解。

是否有用于Python的GPS库？

2 个答案: