我有一个数组NSMutableArray
,其值为
10,2,13,4。
还有NSMutableDictionary
值
(10,a),(20,b),(13,c),(2,d),(33,e)
我想在NSMutableDictionary
中对dict的结果进行排序,dict的结果应该是(10,a),(2,d),(13,c)
答案 0 :(得分:1)
我为你写的功能。希望,它会帮助你:
- (void)removeUnnedful
{
NSMutableDictionary *dict = [[NSMutableDictionary alloc] initWithObjectsAndKeys:
@"a", [NSNumber numberWithInt:10],
@"b", [NSNumber numberWithInt:20],
@"c", [NSNumber numberWithInt:13],
@"d", [NSNumber numberWithInt:2 ],
@"e", [NSNumber numberWithInt:33],
nil];
NSMutableArray *array = [[NSMutableArray alloc] initWithObjects:
[NSNumber numberWithInt:10],
[NSNumber numberWithInt:2 ],
[NSNumber numberWithInt:13],
[NSNumber numberWithInt:14], nil];
NSMutableDictionary *newDict = [[NSMutableDictionary alloc] init];
for (NSNumber *key in [dict allKeys])
{
NSLog(@"%@", key);
if ([array containsObject:key])
{
[newDict setObject:[dict objectForKey:key] forKey:key];
}
}
for (NSNumber *key in [newDict allKeys])
NSLog(@"key: %@, value: %@", key, [newDict objectForKey:key]);
[dict release];
[array release];
}
答案 1 :(得分:1)
未定义NSDictionary
实例中的键和值的排序顺序。 (见[NSDictionary allKeys]
)
由于您已经有一系列有序键,您可以简单地迭代它并访问该键的字典值:
NSMutableArray* sortedArray = [NSMutableArray arrayWithObjects:@"10", @"2", @"13", @"4", nil];
NSDictionary* dictionary = [NSDictionary dictionaryWithObjectsAndKeys:@"a", @"10", @"b", @"20", @"c", @"13", @"d", @"2", @"e", @"33" , nil];
NSMutableDictionary* filteredDictionary = [NSMutableDictionary dictionary];
for(id key in sortedArray)
{
id value = [dictionary objectForKey:key];
if(value != nil)
{
[filteredDictionary setObject:[dictionary objectForKey:key] forKey:key];
}
}
NSLog(@"%@", filteredDictionary);
请注意,[NSDictionary description]
的默认实现对每个键的输出升序排序(对于NSString
类型的键),但这只是一种表示 - NSDictionaries
没有已定义的排序顺序,所以您不应该依赖allKeys
和allValues