Question

我可能发现了一个错误，如果是这样，我也会报告这个错误？

这就是我所拥有的：

for ($i = 0; $i <= ($count)-1; ++$i) {
 Lots of code...more then I want to put here
....
.....
.....
$mailto = $mailto . $i +1 . ") " . $name . " " . $location . " Type: " . $type . " Status: " . $geostatus . " Difficulty " .$difficulty . "\n" . $region . "\nHidden: " . $hidden . " Last Update: " . $lastupdate . " Last Found: " . $lastfound . "\nDistance: $distance Bearing: $bearing degrees $direction\n\n";
}

echo "$mailto \n";

输出将如下所示：

4) Morrow Parking - RR Relic LMBT Lat: 39.35455 Lon: -84.133733 Type: Traditional Cache Status: Active Difficulty 3
City/State: Morrow, OH Warren Co.
Hidden: Wed June 09 2010 04:00 Last Update: Wed August 03 2011 17:43 Last Found: Wed December 31 1970 19:00
Distance: 4.31 Bearing: 212 degrees SW

仅向我显示列表中的最后一项。但是，如果我稍微改变代码：

for ($i = 0; $i <= ($count)-1; ++$i) {
 Lots of code...more then I want to put here
....
.....
.....
$cc = $i +1;
$mailto = $mailto . $cc . ") " . $name . " " . $location . " Type: " . $type . " Status: " . $geostatus . " Difficulty " .$difficulty . "\n" . $region . "\nHidden: " . $hidden . " Last Update: " . $lastupdate . " Last Found: " . $lastfound . "\nDistance: $distance Bearing: $bearing degrees $direction\n\n";
}

echo "$mailto \n";

我得到的完整输出正如我所期望的那样：

1) Uranus - The Solar System - Lil Miami Bike Trail Lat: 39.415517 Lon: -84.103383 Type: Traditional Cache Status: Active Difficulty 1.5
City/State: , OH Warren Co.
Hidden: Sun October 17 2010 04:00 Last Update: Fri August 05 2011 18:25 Last Found: Wed December 31 1970 19:00
Distance: 0.92 Bearing: 309 degrees NW

2) 79 Lat: 39.394517 Lon: -84.096533 Type: Traditional Cache Status: Active Difficulty 2
City/State: , OH Warren Co.
Hidden: Sun May 30 2010 04:00 Last Update: Wed August 03 2011 17:42 Last Found: Wed December 31 1970 19:00
Distance: 0.93 Bearing: 201 degrees S

3) RR Relic - Oregonia Lat: 39.462583 Lon: -84.100383 Type: Traditional Cache Status: Active Difficulty 1.5
City/State: Oregonia, OH Warren Co.
Hidden: Sun May 02 2010 04:00 Last Update: Wed August 03 2011 17:41 Last Found: Wed December 31 1970 19:00
Distance: 3.88 Bearing: 351 degrees N

4) Morrow Parking - RR Relic LMBT Lat: 39.35455 Lon: -84.133733 Type: Traditional Cache Status: Active Difficulty 3
City/State: Morrow, OH Warren Co.
Hidden: Wed June 09 2010 04:00 Last Update: Wed August 03 2011 17:43 Last Found: Wed December 31 1970 19:00
Distance: 4.31 Bearing: 212 degrees SW

我是否发现了一个错误，或者我是否在第一种方式做错了什么，并在第二种方式中纠正错误？

如果我确实发现了一个错误，我也会报告错误。

PHP v5.3.3在Ubuntu 10.10上运行CLI版本谢谢。

Answer 1

在代码的第一位，更改：

$mailto = $mailto . $i +1 . ") " . $name . " " . $location . " Type: " . $type . " Status: " . $geostatus . " Difficulty " .$difficulty . "\n" . $region . "\nHidden: " . $hidden . " Last Update: " . $lastupdate . " Last Found: " . $lastfound . "\nDistance: $distance Bearing: $bearing degrees $direction\n\n";

到

$mailto = $mailto . ($i +1) . ") " . $name . " " . $location . " Type: " . $type . " Status: " . $geostatus . " Difficulty " .$difficulty . "\n" . $region . "\nHidden: " . $hidden . " Last Update: " . $lastupdate . " Last Found: " . $lastfound . "\nDistance: $distance Bearing: $bearing degrees $direction\n\n";

我怀疑你的操作顺序错误。

Answer 2

它与运算符优先级有关。这是一个简化的例子：

$i=1;// doesn't matter what this value is
$s = " alpha " . $i+1 .  " beta " . " gamma<br>\n";
echo $s; // 1 beta gamma

$s = " alpha " . ($i+1) .  " beta " . " gamma<br>\n";
echo $s; // alpha 2 beta gamma

第一种情况下的奇怪行为甚至发生在你加入一个（int）。

$s = " alpha " . (int)$i+1 .  " beta " . " gamma<br>\n";

我想在PHP v5.3.3-1ubuntu9.5 CLI中发现了一个错误？

2 个答案: